我想创建一个服务,将返回从PHP API,JSON数据,而不是返回纯JSON数据,角似乎返回与其配置的JSON。角度返回的数据
services.js
.service('DistinctAPIService', function($http){
var base = 'http://localhost/onseral/api/';
this.listDistinct = function(table, field){
return $http({
method: 'POST',
url: base + '/listDistinct.php',
params: {
table: table,
field: field
}
});
}
})
.controller('DistinctMatcode', function($scope, DistinctAPIService){
DistinctAPIService.listDistinct('material', 'matcode').then(function(data){
$scope.data = data;
console.log(JSON.stringify(data));
})
})
listdistinct.php
<?php
require_once '/config/dbconfig.php';
$table = $_GET['table'];
$field = $_GET['field'];
GetData($table,$field);
function GetData($tablename,$fieldname) {
$sql = "SELECT DISTINCT $fieldname as expr1 FROM $tablename order by expr1 asc";
try {
$db = getdb();
$stmt = $db->prepare($sql);
$stmt->execute();
$data = $stmt->fetchAll(PDO::FETCH_OBJ);
$db = null;
echo json_encode(array('data' => $data));
} catch(PDOException $e) {
echo '{"error":{"text":'. $e->getMessage() .'}}';
}
}
?>
,而不是返回正确的JSON数据,它返回
{"data":{"data":[{"expr1":"CFFBPS16"}]},"status":200,"config":{"method":"POST","transformRequest":[null],"transformResponse":[null],"url":"http://localhost/onseral/api//listDistinct.php","params":{"table":"material_copy","field":"matcode"},"headers":{"Accept":"application/json, text/plain, */*"}},"statusText":"OK"}
什么想法?
它删除'{ “数据”:'但仍然有另一个'{ “数据”:',我只想得到的结果为'[{“表达式1 “:”value“}] –
试试这个$ scope.data = data.data.data –
很好,它的工作 –