2011-06-06 72 views
0

这是您每天上传并裁剪“简介”图片脚本/函数。有人浏览他们的电脑并上传图片。这个图像然后被上传到一个单独的服务器。在此之后,同样的图像被提出来让他们“裁剪”,然后保存该新版本并移除旧的大图像。我有这一切运作良好,除了一个小细节...ftp_put():在将图像添加到单独的服务器时,它也将其添加到本地服务器

一旦他们保存裁剪版本,它也保存到主目录中的本地服务器。我无法弄清楚为什么它会这样做,因为它专门设置为仅上传到另一个。

这里是信息:

$upload_dir = "profile_images/". $username;   // The directory for the images to be saved in 
$upload_path = $upload_dir."/";    // The path to where the image will be saved 
$large_image_name = "resized_pic.jpg";  // New name of the large image 
$thumb_image_name = $userid ."00". $i .".jpg"; // New name of the thumbnail image 
$max_file = "200000";      // Approx 200kb 
$max_width = "500";       // Max width allowed for the large image 
$thumb_width = "80";      // Width of thumbnail image 
$thumb_height = "80";      // Height of thumbnail image 

//Image Locations 
$large_image_location = $upload_path.$large_image_name; 
$thumb_image_location = $upload_path.$thumb_image_name; 

这里是调整裁剪图像的功能:

function resizeThumbnailImage($thumb_image_name, $image, $width, $height, $start_width, $start_height, $scale){ 
global $ftp_server; 
global $ftp_user_name; 
global $ftp_user_pass; 
global $thumb_image_location; 
global $large_image_location; 
global $user; 
global $userid; 
global $username; 
global $success; 
global $error; 

$conn_id = ftp_connect($ftp_server); 

// login with username and password 
$login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass); 
ftp_pasv($conn_id, true); 

if ($login_result) { 
    $newImageWidth = ceil($width * $scale); 
    $newImageHeight = ceil($height * $scale); 
    $newImage = imagecreatetruecolor($newImageWidth,$newImageHeight); 
    $source = imagecreatefromjpeg($image); 
    imagecopyresampled($newImage,$source,0,0,$start_width,$start_height,$newImageWidth,$newImageHeight,$width,$height); 
    imagejpeg($newImage,$thumb_image_name,90); 
    // chmod($thumb_image_name, 0777); 

    $upload = ftp_put($conn_id, $thumb_image_location, $thumb_image_name, FTP_BINARY);// upload the file 
    ftp_chmod($conn_id, 0777, $thumb_image_location); 

    if ($upload) { 
     // User DB Queries 
     $time = strtotime("now"); 
     $time = $time + 3600; 
     $date = date(c, $time); 
     $path = 'http://www.otherserver.net/'. $thumb_image_location; 

     $fileQuery = "INSERT INTO `avatars`(userid, username, path, date) VALUES('$userid', '$username', '$path', '$date')"; 
     $fileResult = mysql_query($fileQuery); 
     $userQuery = "UPDATE `users` SET avatar = '$path' WHERE username = '$user'"; 
     $userResult = mysql_query($userQuery); 

     if ($fileResult && $userResult) { 
      $success = 'Your avatar has been uploaded successfully.'; 
     } else { 
      $error = 'Something went wrong with your upload.'; 
     } 
    } 
} 
ftp_close($conn_id); // close the FTP stream 
} 

最后,这里是当函数被调用:

if (isset($_POST["upload_thumbnail"]) && strlen($large_photo_exists) > 0) { 
    //Get the new coordinates to crop the image. 
    $x1 = $_POST["x1"]; 
    $y1 = $_POST["y1"]; 
    $x2 = $_POST["x2"]; 
    $y2 = $_POST["y2"]; 
    $w = $_POST["w"]; 
    $h = $_POST["h"]; 
    //Scale the image to the thumb_width set above 
    $scale = $thumb_width/$w; 
    resizeThumbnailImage($thumb_image_name, "http://otherserver.net/". $large_image_location,$w,$h,$x1,$y1,$scale); 

} 

再次,一切工作正常,除了它保存最终(裁剪)的图像到本地服务器以及(是的,我t也将它保存到另一台服务器上,这样一部分就可以了)。

+0

全部固定。我只是不得不“解除”上传到本地服务器的图像。 – Nate 2011-06-07 05:20:07

回答

0

嗯,你做两件事情:

  • imagejpeg磁盘创建JPG,叫$thumb_image_name
  • 上传JPG到FTP服务器ftp_put

你永远不删除本地文件,所以它仍然存在。

+0

这将是有道理的哈哈...有无论如何使imagejpeg()在FTP服务器上工作?所以它不会上传到本地?我希望本地服务器没有任何事情发生,我需要它在FTP服务器上完成所有操作:/我试图使它$ thumb_image_name = imagejpeg($ newImage,$ thumb_image_name,90);但它失败了。 – Nate 2011-06-06 23:17:23