简单的形式不通过所有变量？

我有一个简单的表单，它使用ajax将数据发送到发送电子邮件的php脚本。它的工作很好，只是名称字段，但是当我是f_name和l_name它似乎不通过它们？简单的形式不通过所有变量？

的HTML是

body { font-family:Arial, Helvetica, sans-serif; font-size:13px; color:#444; } 

input[type=text], input[type=email], textarea { 
    border:1px solid #ccc; 
    padding:8px; 
    margin:2px 0; 
    font-size:13px; 
    font-family:Arial, Helvetica, sans-serif; 
    color:#8f8f8f; 
    width:250px; 
    border-radius:5px; 
    box-shadow:inset 0 0 8px #e5e8e7; 
} 
input[type=submit] { 
    border:none; 
    padding:8px 25px; 
    margin:2px 0; 
    font-family:Arial, Helvetica, sans-serif; 
    color:#fff; 
    background:#0d7963; 
    border-radius:5px; 
    cursor:pointer; 
} 
input[type=submit]:hover { 
    opacity:0.9; 
} 
</style> 
<script src="/js/jquery.min.js"></script> 
<script> 
$(document).ready(function() { 
    $('.myform').on('submit',function(){ 

     // Add text 'loading...' right after clicking on the submit button. 
     $('.output_message').text('Processing...'); 

     var form = $(this); 
     $.ajax({ 
      url: form.attr('action'), 
      method: form.attr('method'), 
      data: form.serialize(), 
      success: function(result){ 
       if (result == 'success'){ 
        $('.output_message').text('Message Sent!'); 
       } else { 
        $('.output_message').text('Error Sending email!'); 
       } 
      } 
     }); 

     // Prevents default submission of the form after clicking on the submit button. 
     return false; 
    }); 
}); 
</script> 
</head> 
<body> 
<form method="post" class="myform" action="process-form3.php"> 
    <input type="text" name="f_name" placeholder="Your first Name" required><br> 
    <input type="text" name="l_name" placeholder="Your last Name" required><br> 

    <input type="email" name="email" placeholder="Your Email" required><br> 
    <textarea rows="4" cols="20" name="message" placeholder="Your Message"></textarea><br> 
    <input type="submit" name="send" value="Send"> <span class="output_message"></span> 
</form>

php文件是：

<?php 
if (isset($_REQUEST['f_name'],$_REQUEST['email'])) { 

    $f_name = $_REQUEST['f_name']; 
    $l_name = $_REQUEST['l_name']; 
    $email = $_REQUEST['email']; 
    $message = $_REQUEST['message']; 

$new_message = $message+f_name+l_name; 


    // Set your email address where you want to receive emails. 
    $to = '[email protected]'; 

    $subject = 'Contact Request From Website'; 
    $headers = "From: ".$name." <".$email."> \r\n"; 

    $send_email = mail($to,$subject,$new_message,$headers); 

    echo ($send_email) ? 'success' : 'error'; 

} 
?>

来源

2017-02-12 Jules

我发现了一些问题：

你concatening PHP串像JavaScript这里：

$new_message = $message+f_name+l_name;

与只需更换：

$new_message = $message . $f_name . $l_name;

显然，$name没有在这里定义：

$headers = "From: ".$name." <".$email."> \r\n";

我认为这就是它！

来源

2017-02-12 13:21:08 mrlew

问题就在这里：

$headers = "From: ".$name." <".$email."> \r\n";

你应该定义$name或使用$f_name一个或$l_name

来源

2017-02-12 13:25:06

谢谢，我已经做到了，但必须改回我的意外，做工精细，谢谢 – Jules

错串接在这一行：

$new_message = $message+f_name+l_name;

它应该是这个样子：

$new_message = $message.$f_name.$l_name;

，你也需要更换$在这一行$ f_name名称：

$headers = "From: ".$name." <".$email."> \r\n";

你去那里;）

来源

2017-02-12 13:46:12 bob

简单的形式不通过所有变量？

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