使用COUNT的Mysql insde CASE

Question

是否可以在CASE中使用count，这里是我的查询。给我一个错误＃1111

SELECT t1.id,t1.name,t1.date_entered,t1.date_modified, t1.adresse,t1.adresse_state,t1.adresse_city,t1.adresse_postalcode,t1.hausnummer,t1.center_lat,t1.center_long, t3.name as street_name,t3.strasse,t3.primaerstr 
FROM hi_haus as t1 
LEFT JOIN hi_haus_hi_strasse as t2 ON (t2.hi_haus_id = t1.id) 
LEFT JOIN hi_strasse as t3 ON (t3.id = t2.hi_strasse_id) 
WHERE t1.adresse !='' AND t1.adresse IS NOT NULL AND t1.adresse NOT LIKE '%bau%' AND t1.id IN ('58e722d6-44f5-4e24-8861-5cd4a6f07cbc','4d0a79ee-decf-49b1-8b4b-a912b278ffec') 
AND t3.primaerstr = 
CASE 
WHEN count(t1.id) > '1' THEN t3.primaerstr='0' 
ELSE 
t3.primaerstr = '1' 
END 
GROUP BY t1.id 

我需要做的是让primaerstr“0”，如果ID被重复多次。

Answer 1

SELECT t1.id，t1.name，t1.date_entered，t1.date_modified，t1.adresse，t1.adresse_state，t1.adresse_city，t1.adresse_postalcode，T1。 hausnummer，t1.center_lat，t1.center_long，t3.name as street_name，t3.id，t3.strasse，t3.primaerstr FROM hi_haus as t1 LEFT JOIN hi_haus_hi_strasse as t2 ON（t2.hi_haus_id = t1.id）LEFT JOIN hi_strasse as t3 ON（t3.id = t2.hi_strasse_id）WHERE t1.adresse！=''AND t1.adresse IS NOT NULL AND t1.adresse NOT LIKE'％bau％'AND t1.id IN（'58e722d6-44f5-4e24- 8861-5cd4a6f07cbc'，'5d492f56-c26e-4c03-b3ec-e1d9b0c6f060'，'fc87b46a-5fe8-4ed0-b3f4-f6fbb0d6919d'）AND t3.primaerstr！=（CASE WHEN（SELE CT COUNT（hi_haus_id）FROM hi_haus_hi_strasse WHERE hi_haus_id = t1.id）> 1 THEN 1 ELSE''END）ORDER BY t1.id，t1.date_modified DESC LIMIT 30;

Answer 2

试试这个

SELECT t1.id , t1.name , t1.date_entered , t1.date_modified , t1.adresse , t1.adresse_state , t1.adresse_city , t1.adresse_postalcode , t1.hausnummer , t1.center_lat , t1.center_long , t3.name AS street_name , t3.strasse , t3.primaerstr FROM hi_haus AS t1 , (SELECT id , COUNT(*) AS count FROM hi_haus GROUP BY id ) AS subquery LEFT JOIN hi_haus_hi_strasse AS t2 ON (t2.hi_haus_id = t1.id) LEFT JOIN hi_strasse AS t3 ON (t3.id = t2.hi_strasse_id) WHERE t1.adresse != '' AND t1.adresse IS NOT NULL AND t1.adresse NOT LIKE '%bau%' AND t1.id IN ('58e722d6-44f5-4e24-8861-5cd4a6f07cbc', '4d0a79ee-decf-49b1-8b4b-a912b278ffec') AND ((t3.primaerstr = 0 AND t1.id = subquery.id AND subquery.count > 1) OR (t3.primaerstr = 1 AND t1.id = subquery.id AND subquery.count = 0) ) GROUP BY t1.id