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我写了一个SQL查询,并试图使其适应Sequelize,但无法弄清楚如何在同一张表上创建关联。下面是SQL:内部加入同一张表Sequelize
SELECT t1.*
FROM `configurations` t1
INNER JOIN
(
SELECT max(configuration_start) maxConfigStart, pb_id
FROM `configurations`
WHERE
active = 1
AND DATE(configuration_start) <= DATE(NOW())
GROUP BY `pb_id`
) t2
ON t1.`pb_id` = t2.`pb_id`
AND t1.`configuration_start` = t2.`maxConfigStart`
WHERE t1.`active` = 1
ORDER BY t1.`configuration_start` DESC
下面是模型定义:
configurations = sequelize.define 'configurations', {
id:
type: Sequelize.INTEGER
primaryKey: true
autoIncrement: true
configuration_name: Sequelize.STRING
pb_id: Sequelize.INTEGER
device_id: Sequelize.STRING
event_id: Sequelize.INTEGER
configuration_start: Sequelize.DATE
configuration_end: Sequelize.DATE
utc_offset: Sequelize.STRING
watermark_id: Sequelize.INTEGER
ipad_config_id: Sequelize.INTEGER
screen_group_id: Sequelize.INTEGER
color_table_id: Sequelize.INTEGER
animated_overlay_group: Sequelize.INTEGER
created: Sequelize.DATE
updated: Sequelize.DATE
active: Sequelize.INTEGER
}, {
timestamps: false,
scopes: {
currentConfigTimes: {
attributes: ['pb_id', [sequelize.fn('max', sequelize.col('configuration_start')), 'configuration_start']]
where:
active: 1
configuration_start:
lte: new Date()
group: ['pb_id']
},
currentConfigIds: {
attributes: ['pb_id', 'configuration_start', 'id']
where:
active: 1
configuration_start:
lte: new Date()
order: [['configuration_start', 'DESC']]
}
}
}
任何帮助,有人可以提供将非常感激。本质上,我试图为每个pb_id
获取最新的过去配置。也许有更好的方法来做到这一点?
你SQL看起来没有问题,你不需要最后的地方......那么你的问题是什么? – SIDU
我不知道如何在Sequelize中做到这一点。我可以在SQL中做到这一点,但不知道如何将其转移到我的ORM。 – tonestrike