我想标注一个Java类创建JAXB模式与具有价值属性的元素。代码如下:带有Object类型的JAXB属性抛出空指针异常?
@XmlAttribute(name="value")
public Object getSettingValue() {
return this.settingValue;
}
public void setSettingValue(final Object settingValue) {
this.settingValue = settingValue;
}
当我尝试生成模式(使用Eclipse的非莫西实现),我得到这个空指针异常:
Exception in thread "main" java.lang.NullPointerException
at com.sun.xml.internal.bind.v2.runtime.reflect.TransducedAccessor.get(TransducedAccessor.java:154)
at com.sun.xml.internal.bind.v2.runtime.property.AttributeProperty.<init>(AttributeProperty.java:56)
at com.sun.xml.internal.bind.v2.runtime.property.PropertyFactory.create(PropertyFactory.java:93)
at com.sun.xml.internal.bind.v2.runtime.ClassBeanInfoImpl.<init>(ClassBeanInfoImpl.java:145)
at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl.getOrCreate(JAXBContextImpl.java:479)
at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl.<init>(JAXBContextImpl.java:305)
at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl$JAXBContextBuilder.build(JAXBContextImpl.java:1100)
at com.sun.xml.internal.bind.v2.ContextFactory.createContext(ContextFactory.java:143)
at com.sun.xml.internal.bind.v2.ContextFactory.createContext(ContextFactory.java:110)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:597)
at javax.xml.bind.ContextFinder.newInstance(ContextFinder.java:202)
at javax.xml.bind.ContextFinder.find(ContextFinder.java:376)
at javax.xml.bind.JAXBContext.newInstance(JAXBContext.java:574)
at javax.xml.bind.JAXBContext.newInstance(JAXBContext.java:522)
at org.eclipse.jpt.jaxb.core.schemagen.Main.buildJaxbContext(Main.java:95)
at org.eclipse.jpt.jaxb.core.schemagen.Main.generate(Main.java:76)
at org.eclipse.jpt.jaxb.core.schemagen.Main.execute(Main.java:62)
at org.eclipse.jpt.jaxb.core.schemagen.Main.main(Main.java:47)
当我做了这个一个@XmlElement代替一个属性,模式生成没有问题,所以它必须与此相关。有任何想法吗?
您的属性必须是“对象”类型还是可以将其更改为“字符串”? – 2013-02-15 17:14:07
@BlaiseDoughan我们将传入各种类型的对象 - 整型,布尔或字符串(也可能是其他类型,因为我们扩展了我们的应用程序)。我不知道我们是否可以将其更改为字符串。我们可以创建一个独立的setter,它将采用String。 – chama 2013-02-15 17:24:29
@BlaiseDoughan我可以改变它的字符串,然后通过我的真实方法。谢谢! – chama 2013-02-15 17:42:09