我试图让我的第一个servlet在eclipse中为tomcat 7.0运行在j2ee上,但我无法弄清楚我做错了什么。我像这样运行整个项目:右键单击我的项目 - >运行方式 - >在服务器上运行,index.html文件在浏览器中显示给我,但是当我点击“继续”时,它向我显示以下消息:如何让我的第一个servlet工作?
HTTP状态404 -/PDPJ_L5 /你好 - 该 请求的资源(/ PDPJ_L5 /你好)是 不可用。
我怀疑问题出在form标记的action属性上,或者是web描述符文件中。请解释我做错了什么以及如何修复我的项目。谢谢。
这里是我的项目(PDPJ_L5)目录结构:
PDPJ_L5
- JAX-WS Web服务
- 部署描述符:PDPJ_L5
- Java的资源:SRC其中包含的servlet用我的Hello.java servlet包装
- JavaScript资源
- 构建
- META-INF
- WEB-INF一个lib文件夹,我的index.html和web.xml
的index.html的内容:
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Some title</title>
</head>
<body>
<H1 ALIGN="CENTER">Choose your option:</H1>
<form action="http://localhost:8080/PDPJ_L5/hello" method="GET">
<center>
<INPUT TYPE="RADIO" NAME="group" VALUE="one">ONE<BR>
<INPUT TYPE="RADIO" NAME="group" VALUE="two">TWO<BR><BR>
<INPUT TYPE="SUBMIT" VALUE="Continue">
</center>
</form>
</body>
</html>
这里是Hello.java的servlet:
package servlets;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class Hello
*/
public class Hello extends HttpServlet
{
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public Hello()
{
super();
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
{
response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<HEAD><TITLE>Success</HEAD><BODY>");
out.println("<h1> It works </h1>");
out.println("</BODY>");
out.close();
}
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
{
doGet(request, response);
}
}
而且web.xml文件:
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-application_2_3.dtd">
<web-app>
<servlet>
<servlet-name>Hello</servlet-name>
<servlet-class>servlets.Hello</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Hello</servlet-name>
<url-pattern>/hello</url-pattern>
</servlet-mapping>
</web-app>
我很惊讶默认的web.xml Eclipse创建的指向Servlet 2.3 * http://java.sun.com/dtd/web-application_2_3.dtd*?我有* web-app_2_5.xsd * – JoseK 2010-11-22 13:55:33
@Jose:他读大量过时的教程/书籍的机会很大,1998年以来弃用的'