检查密码的强度

Question

我不想找人给我解决方案。 我只是寻求一些帮助，为什么这不起作用。 这也是一点点比其他可用的密码强度问题

def password(pwd): 
     if len(pwd) >= 10: 
      is_num = False 
      is_low = False 
      is_up = False 
      for ch in pwd: 
       if ch.isdigit(): 
        is_num = True 
       if ch.islower(): 
        is_low = True 
       if ch.isupper(): 
        is_up = True 

if __name__ == '__main__': 
    #These "asserts" using only for self-checking and not necessary for auto-testing 
    assert password(u'A1213pokl') == False, "1st example" 
    assert password(u'bAse730onE4') == True, "2nd example" 
    assert password(u'asasasasasasasaas') == False, "3rd example" 
    assert password(u'QWERTYqwerty') == False, "4th example" 
    assert password(u'123456123456') == False, "5th example" 
    assert password(u'QwErTy911poqqqq') == True, "6th example" 

Answer 1

你错过了2条return语句，使这项工作不同：

def password(pwd): 
    if len(pwd) >= 10: 
     is_num = False 
     is_low = False 
     is_up = False 
     for ch in pwd: 
      if ch.isdigit(): 
       is_num = True 
      if ch.islower(): 
       is_low = True 
      if ch.isupper(): 
       is_up = True 
     return is_num and is_low and is_up 
    return False 

Answer 2

def password(pwd): 
     upper = any(ch.isupper() for ch in pwd) 
     lower = any(ch.islower() for ch in pwd) 
     is_dig = any(ch.isdigit() for ch in pwd) 
     return upper and lower and is_dig and len(pwd) > 10