-3
好吧,所以我试图做一个简单的表单,其中用户点击一个按钮,通过输入表添加一段数据,然而无论何时我输入内容并提交如果没有通过数据库和想法为什么?数据没有插入(php到phpmyadmi数据库)
<?php
$connect = mysqli_connect('localhost','username','','password');
if (!$connect){die("Can not connect:". mysqli_error());}
$db = new mysqli('localhost','uername','','password');
if (isset($_POST['add_sd']) && $_POST['add_sd']){
echo "<table cellpadding = 5px><tr><td><input type = text name = stdn_add placeholder= 'Type in The Student Number' /></td></tr>
<tr><td><input type = text name = fname_add placeholder = 'Type in their First Name'/></td><td><input type = text name = lname_add placeholder = 'Type in their Last Name'/></td></tr>
<tr><td><select name = feet><option></option><option value = 4 > 4 </option><option value = 5> 5 </option><option value = 6> 6 </option></select> Feet </td>
<td><select name = inches><option></option><option value = 0> 0 </option><option value = 1> 1 </option><option value = 2> 2 </option><option value = 3> 3 </option><option value = 4> 4 </option><option value = 5> 5 </option><option value = 6> 6 </option><option value = 7> 7 </option><option value = 8> 8 </option><option value = 9> 9 </option><option value = 10> 10 </option><option value = 11> 11 </option></select>Inches</td></tr>
<tr><td><input type = radio name = e_n value = 'Enable FullFit' /></td><td><input type = radio name = d_n value = 'Disable FullFit' /></td></tr>
<tr><input type = submit name = submit_edit value = 'Submit' /></tr>
</table>";
}
if (isset($_POST['e_n']) && $_POST['e_n']){$ff = "FF";}
else if(isset($_POST['d_n']) && $_POST['d_n']){$ff = " ";}
if (isset($_POST['stdn_add']) && $_POST['stdn_add'] && isset($_POST['fname_add']) && $_POST['fname_add'] && isset($_POST['lname_add']) && $_POST['lname_add'] && isset($_POST['feet']) && $_POST['feet'] && isset($_POST['inches']) && $_POST['inches'] && isset($_POST['e_n']) && $_POST['e_n'] && isset($_POST['d_n']) && $_POST['d_n'] && isset($_POST['submit'])){
$insertinto_profile = $db -> query("INSERT INTO `profile` VALUES ('".$_POST['fname_add']."','".$_POST['lname_add']."','".$_POST['stdn_add']."',NULL,NULL,1234)");
$insertinto_grad_specs = $db -> query("INSERT INTO `grad_specs` VALUES (NULL,'".$_POST['stdn_add']."','".$_POST['stdn_add']."','".$_POST['stdn_add']."','0','$ff','".$_POST['fname_add']."','".$_POST['lname_add']."')");
$insertinto_info = $db -> query("INSERT INTO `excel_info` VALUES (NULL,'".$_POST['stdn_add']."','".$_POST['fname_add']."','".$_POST['lname_add']."','0','$ff')");
}
?>
-1没有调试工作,也没有努力保护您的代码。另外,感谢您的密码。 –
语法lgtm,准备好的语句,编码风格指南和mysqli :: $ error是你的朋友 – worenga