用不同的标准在同一张桌子上加入不同的行

我试着问了一些问题，并用Google搜索，结果我发现一个查询可以在各种可能的意义上杀死数据库。用不同的标准在同一张桌子上加入不同的行

我有3个表：

jiraissue保留有关JIRA门票的信息（其谁分配）。

changegroup这将保持更改日期，票证的ID被更改并且ID将更改为更改详细信息。

changeitem包含更改ID，更改字段和新/旧值。

我想以下输出：

[time_taken_to_resolve]，[assigned_date]，[resolve_date]，[jira_ticket_details_from_jiraissue]

Criteria是jiraissue.ASSIGNEE值。

我想出了以下内容：如果我使用一个特定jiraissue.id

SELECT TIMESTAMPDIFF(HOUR,a.assigned_date,b.resolved_date),a.*, b.* 
FROM jiraissue 
INNER JOIN (
    SELECT changegroup.CREATED as "assigned_date",changegroup.issueid as jid 
    FROM changegroup 
    JOIN changeitem ON changegroup.ID = changeitem.groupid 
    WHERE changeitem.FIELD="assignee" 
    GROUP BY changegroup.issueid 
    ORDER BY changegroup.CREATED DESC 
) as a ON a.jid = jiraissue.id 
INNER JOIN ( 
    SELECT changegroup.CREATED as "resolved_date", changegroup.issueid as jid 
    FROM changegroup 
    JOIN jiraissue on changegroup.issueid = jiraissue.ID 
    JOIN changeitem ON changegroup.ID = changeitem.groupid 
    WHERE changeitem.FIELD="status" AND changeitem.NEWVALUE=5 
    GROUP BY changegroup.issueid 
    ORDER BY changegroup.CREATED DESC 
) as b ON b.jid = jiraissue.id 
WHERE jiraissue.ASSIGNEE = "gangsta";

上面的查询工作，但如果我被jiraissue.ASSIGNEE搜索（它进行运算）。

另外我对最近解决和分配的日期感兴趣，可能有很多，但我想每个的最后一个。

任何帮助，非常感谢。

谢谢。

来源

2015-10-06 MostWanted

你应该分析你的索引。我认为你有一个由jiraissue.id，但没有由jiraissue.ASSIGNEE。对于上次解析和分配的日期，您可以在连接中使用max（）。 –

想出了这个，似乎这样的伎俩：

SELECT TIMESTAMPDIFF(HOUR,a.assigned_date,b.resolved_date),a.*, b.*,jiraissue.* 
FROM jiraissue 
INNER JOIN (
    SELECT MAX(changegroup.CREATED) as "assigned_date",changegroup.issueid as jid 
    FROM changegroup 
    JOIN jiraissue as ji1 ON changegroup.issueid=ji1.id 
    JOIN changeitem ON changegroup.ID = changeitem.groupid 
    WHERE changeitem.FIELD="assignee" AND ji1.ASSIGNEE="gangsta" AND issuetype = 5 AND PRIORITY = 4 
    GROUP BY changegroup.issueid 
) as a ON a.jid = jiraissue.id 
INNER JOIN (
    SELECT MAX(changegroup.CREATED) as "resolved_date", changegroup.issueid as jid 
    FROM changegroup 
    JOIN jiraissue as ji2 ON changegroup.issueid=ji2.id 
    JOIN changeitem ON changegroup.ID = changeitem.groupid 
    WHERE changeitem.FIELD="status" AND changeitem.NEWVALUE=5 AND ji2.ASSIGNEE="gangsta" AND issuetype = 5 AND PRIORITY = 4 
    GROUP BY changegroup.issueid 
) as b ON b.jid = jiraissue.id 
ORDER BY b.resolved_date DESC;

来源

2015-10-06 10:26:53 MostWanted

用不同的标准在同一张桌子上加入不同的行

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