子查询在group by子句中返回多于一行 - MySQL

Question

我试图使用查询的正确总和查询我的查询的预期结果，但是，当它检测到相同的ID时，这些数字会不断累加。我想按日期获得小组。不幸的是，当我跑我的查询它得到一个错误说子查询返回多个1行

这里是我的查询：

SELECT a.DOB as `DATE`, (CASE when f.INHOUR > 12 or f.INHour = 12 Then 'PM' 
else 'AM' END) as Shift, concat(b.FIRSTNAME, ' ', b.LASTNAME) Fullname, 
a.Amount as DECLARED, SUM(c.Amount) as CALCULATED, 
a.AMOUNT as `NET OF SPECIAL SALES`, 
d.Amount as `CASH OVER SHORT`, 
a.AMOUNT as `CASH DEPOSIT`, 
(SELECT SUM(gndrevn.AMOUNT) from gndrevn where gndrevn.ID= b.ID and 
gndrevn.type = "4" group by gndrevn.DOB, gndrevn.ID) as `TRANSACTION COUNT (POS)` 
FROM gndsale a 
INNER JOIN emp b ON a.ID= b.ID 
INNER JOIN gndsale c ON b.ID= c.ID 
INNER JOIN gndsale d on b.ID = d.ID 
INNER JOIN adjtime f on a.ID= f.ID 
WHERE a.type = "22" AND c.type = "4" AND d.type = "42" and 
STR_TO_DATE(a.DOB, '%m/%d/%Y') BETWEEN '2017-05-01' AND '2017-05-31' GROUP BY DECLARED 
order by STR_TO_DATE(a.DOB, '%m/%d/%Y') 

它返回此错误：

我试图删除gndrevn.DOB，gndrevn.ID，这是我的结果

列交易数POS只是增加了，因为它检测表相似的ID。

什么结果，我想为我的事务数POS是这样的：

我跑这跟不同的查询，但它也通过在select语句

这里需要一组查询：

SELECT ID as `EMPLOYEE`, sum(AMOUNT) as AMOUNT, DOB as DATE from gndrevn 
where ID in (select ID from gndsale) and type = "4" group by 
DOB, ID order by STR_TO_DATE(DOB, '%m/%d/%Y') 

我觉得我的团队通过声明来得到查询有问题。任何人都可以帮助我呢？ :(

Answer 1

我想你想要的是从GROUP BY取出gndrevn.DOB并在WHERE添加gndrevn.DOB = a.DOB。