我记得这个问题而回:How to calculate the difference between two dates using PHP?
有了它看起来像这样一些小的调整:
function convert_number($number) {
$Gn = floor($number/1000000); /* Millions (giga) */
$number -= $Gn * 1000000;
$kn = floor($number/1000); /* Thousands (kilo) */
$number -= $kn * 1000;
$Hn = floor($number/100); /* Hundreds (hecto) */
$number -= $Hn * 100;
$Dn = floor($number/10); /* Tens (deca) */
$n = $number % 10; /* Ones */
$res = "";
if ($Gn)
$res .= convert_number($Gn) . " Million";
if ($kn) {
$res .= (empty($res) ? "" : " ") .
convert_number($kn) . " Thousand";
}
if ($Hn) {
$res .= (empty($res) ? "" : " ") .
convert_number($Hn) . " Hundred";
}
$ones = array("", "One", "Two", "Three", "Four", "Five", "Six","Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen","Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eightteen","Nineteen");
$tens = array("", "", "Twenty", "Thirty", "Fourty", "Fifty", "Sixty","Seventy", "Eigthy", "Ninety");
if ($Dn || $n) {
if (!empty($res))
$res .= " and ";
if ($Dn < 2)
$res .= $ones[$Dn * 10 + $n];
else {
$res .= $tens[$Dn];
if ($n)
$res .= "-" . $ones[$n];
}
}
if (empty($res))
$res = "zero";
return $res;
}
function yearsFromNow ($date) {
return convert_number(floor(abs(strtotime($date) - strtotime(date("Y-m-d")))/(365*60*60*24)));
}
echo yearsFromNow("2007-03-24");
echo yearsFromNow("2009-06-26");
输出:
3210
数以信取本网站修改功能:http://www.phpro.org/examples/Convert-Numbers-to-Words.html
什么版本的PHP安装? – ManseUK 2012-01-06 14:44:01
这只是计算整年?应该很简单,写一个替代 – OptimusCrime 2012-01-06 14:46:47
@OptimusCrime它只是数数整年。你有替代方法来做到这一点?谢谢。 – user1048676 2012-01-06 14:48:28