String.Split（）为一个字符串数组并保存到一个新的数组

Question

所以，我收到一个字符串数组，我想拆分每个元素并将其保存到一个新的数组中，我面对了很多与该和问题想出了一个非常糟糕的解决方案：

String[] timeSlots = { "13:00:00 - 14:00:00", "15:00:00 - 16:00:00","17:00:00 - 18:00:00" }; 
String[] t = new String[6]; 
String temp[] = new String[6]; 
int j = 1; 
for (int i = 0; i < 3; i++) { 
    temp = timeSlots[i].split("\\-"); 
    if(j == 1){ 
     t[0] = temp[0]; 
     t[1] = temp[1].trim(); 
    } 
    else if(j == 2){ 
     t[2] = temp[0]; 
     t[3] = temp[1].trim(); 
    } 
    else{ 
     t[4] = temp[0]; 
     t[5] = temp[1].trim(); 
    } 
    j++; 
} 

正如你可以看到我必须创建一个if语句，以节省两个要素，我知道这是个不错的办法，但是这就是我能来与：（

Answer 1

您可以从输入数组中的索引计算结果数组中的索引：

String[] t = new String[2*timeSlots.length]; 

for (int i = 0; i < timeSlots.length; i++) { 
    String[] temp = timeSlots[i].split("\\-"); 
    t[2*i] = temp[0].trim(); 
    t[2*i+1] = temp[1].trim(); 
} 

个

或者使用的流：

t = Arrays.stream(timeSlots).flatMap(slot -> Arrays.stream(slot.split("\\-")).map(String::trim)).toArray(String[]::new); 

（然而，这修剪两个字符串）

Answer 2

@Test 
public void splitTimeSlotsToArray() { 
    String[] timeSlots = { "13:00:00 - 14:00:00", "15:00:00 - 16:00:00","17:00:00 - 18:00:00" }; 

    // We already know how many times there are, each range (or slot) 
    // has two times specified in it. So it's the length of timeSlots times 2. 
    String[] times = new String[timeSlots.length*2]; 

    for (int i = 0; i < timeSlots.length; i++) { 
     String timeSlotParts[] = timeSlots[i].split(" - "); 
     times[i*2] = timeSlotParts[0]; 
     times[i*2 + 1] = timeSlotParts[1]; 
    } 

    assertEquals(Arrays.asList(
     "13:00:00", "14:00:00", "15:00:00", "16:00:00", "17:00:00", "18:00:00" 
    ), Arrays.asList(times)); 
} 

// This is a more preferable option in terms of readability and 
// idiomatics in Java, however it also uses Java collections which you 
// may not be using in your class 
@Test 
public void splitTimeSlotsToList() { 
    String[] timeSlots = { "13:00:00 - 14:00:00", "15:00:00 - 16:00:00","17:00:00 - 18:00:00" }; 
    Collection<String> times = new ArrayList<>(); 

    // Go over each time slot 
    for (String timeSlot : timeSlots) { 
     // Go over each time in each time slot 
     for (String time : timeSlot.split(" - ")) { 
      // Add that time to the times collection 
      times.add(time); 
     } 
    } 
    // you can convert the Collection to an array too: 
    // String[] timesArray = times.toArray(new String[timeStamps.size()]); 

    assertEquals(Arrays.asList(
     "13:00:00", "14:00:00", "15:00:00", "16:00:00", "17:00:00", "18:00:00" 
    ), times); 
} 

Answer 3

如果阵列的结构始终是相同的，你可以先加入你的数组中的元素到串并在每小时后再次分割。例如：

public static void main(String a[]){ 
    String[] timeSlots = { "13:00:00 - 14:00:00", "15:00:00 - 16:00:00","17:00:00 - 18:00:00" }; 
    String joined = String.join(" - ", timeSlots);// gives you a string like this "13:00:00 - 14:00:00 - 15:00:00 - 16:00:00 - 17:00:00 - 18:00:00" 
    String [] newArray = joined.split(" - "); 
    System.out.println(Arrays.toString(newArray)); 
}