我正在研究视频游戏库存网站。这里是我的数据库表的简化版本,一些样本数据一起:SQL左加入计数
CREATE TABLE `platforms` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`name` varchar(16) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=4 ;
INSERT INTO `platforms` VALUES(1, 'Nintendo');
INSERT INTO `platforms` VALUES(2, 'Super Nintendo');
INSERT INTO `platforms` VALUES(3, 'Nintendo 64');
--
CREATE TABLE `games` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`platform_id` int(10) unsigned NOT NULL,
`name` varchar(255) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=7 ;
INSERT INTO `games` VALUES(1, 1, 'Super Mario Bros.');
INSERT INTO `games` VALUES(2, 1, 'Super Mario Bros. 2');
INSERT INTO `games` VALUES(3, 2, 'Super Mario World');
INSERT INTO `games` VALUES(4, 2, 'Super Mario Kart');
INSERT INTO `games` VALUES(5, 3, 'Super Mario 64');
INSERT INTO `games` VALUES(6, 3, 'Mario Kart 64');
--
CREATE TABLE `users` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`username` varchar(64) NOT NULL,
`password` varchar(64) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;
INSERT INTO `users` VALUES(1, 'john_doe', '$2a$10$cQhc4VAXVMEyC1tA.VRoWunpNVi7392adacT/weVBzu6XGI6.Jx/K');
INSERT INTO `users` VALUES(2, 'jane_doe', '$2a$10$Ot2BmlT14hKDxHGIV8jBx.lW76HCWdwuOhNGIYrJO5O7BEtDUWLWu');
--
CREATE TABLE `games_users` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`game_id` int(10) unsigned NOT NULL,
`user_id` int(10) unsigned NOT NULL,
`created` datetime NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=5 ;
INSERT INTO `games_users` VALUES(1, 1, 1, '2013-04-12 12:18:09');
INSERT INTO `games_users` VALUES(2, 3, 1, '2013-04-12 12:18:42');
INSERT INTO `games_users` VALUES(3, 4, 1, '2013-04-12 12:19:13');
INSERT INTO `games_users` VALUES(4, 2, 2, '2013-04-12 12:19:32');
正如你所看到的,john_doe即有1级任天堂的游戏(超级马里奥兄弟),2个超级任天堂游戏(超级马里奥世界和超级马里奥卡丁车)和0个任天堂64游戏。 jane_doe有1个任天堂游戏(超级马里奥兄弟2),0个超级任天堂游戏和0个任天堂64游戏。
我想编写一个特定于查询用户的查询,列出所有控制台,并列出用户对每个控制台的游戏数量。
这就是结果会是什么john_doe即:
platform.id: 1
platform.name: Nintendo
game_count: 1
platform.id: 2
platform.name: Super Nintendo
game_count: 2
platform.id: 3
platform.name: Nintendo 64
game_count: 0
这就是结果会是什么jane_doe:
platform.id: 1
platform.name: Nintendo
game_count: 1
platform.id: 2
platform.name: Super Nintendo
game_count: 0
platform.id: 3
platform.name: Nintendo 64
game_count: 0
我怎样才能做到这一点?
你甚至想什么......? –
@HmxaMughal我不知道从哪里开始。对不起,我不是很好 – Nick