0
我有一个自定义的按钮样式以下触发器:样式不适用
<Trigger Property="IsEnabled" Value="true">
<Setter Property="BorderBrush" Value="#FFFFFFFF" />
<Setter Property="Foreground" Value="#FFFFFFFF" />
</Trigger>
<Trigger Property="IsEnabled" Value="false">
<Setter Property="BorderBrush" Value="#FFFF9800" />
<Setter Property="Foreground" Value="#FFFF9800" />
</Trigger>
但他们并不在我的GUI应用在所有。以下是整个风格。
<Window.Resources>
<Style x:Key="Button.Hoverless" TargetType="{x:Type ButtonBase}">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type ButtonBase}">
<Border Name="border"
BorderThickness="{TemplateBinding BorderThickness}"
Padding="{TemplateBinding Padding}"
BorderBrush="{TemplateBinding BorderBrush}"
Background="{TemplateBinding Background}">
<ContentPresenter HorizontalAlignment="Center" VerticalAlignment="Center" />
</Border>
<ControlTemplate.Triggers>
<MultiTrigger>
<MultiTrigger.Conditions>
<Condition Property="IsMouseOver" Value="True" />
<Condition Property="Selector.IsSelected" Value="False" />
</MultiTrigger.Conditions>
<Setter Property="Background" Value="#FFFF9800" />
<Setter Property="Opacity" Value="0.50" />
</MultiTrigger>
<MultiTrigger>
<MultiTrigger.Conditions>
<Condition Property="IsMouseOver" Value="True" />
<Condition Property="Selector.IsSelected" Value="True" />
</MultiTrigger.Conditions>
<Setter Property="Background" Value="#FFFFB850" />
</MultiTrigger>
<MultiTrigger>
<MultiTrigger.Conditions>
<Condition Property="IsMouseOver" Value="False" />
<Condition Property="Selector.IsSelected" Value="True" />
</MultiTrigger.Conditions>
<Setter Property="Background" Value="#FFFF9800" />
</MultiTrigger>
<Trigger Property="IsEnabled" Value="true">
<Setter Property="BorderBrush" Value="#FFFFFFFF" />
<Setter Property="Foreground" Value="#FFFFFFFF" />
</Trigger>
<Trigger Property="IsEnabled" Value="false">
<Setter Property="BorderBrush" Value="#FFFF9800" />
<Setter Property="Foreground" Value="#FFFF9800" />
</Trigger>
<Trigger Property="IsPressed" Value="True">
<Setter TargetName="border" Property="Opacity" Value="0.95" />
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
</Window.Resources>
我是新来的WPF样式,因此我不知道我在哪里出错了。还包括按钮代码:
<Button x:Name="btnScanFP1" Content="Scan Fingerprint" Grid.Column="1"
HorizontalAlignment="Left" Margin="10,10,0,0" Grid.Row="4" VerticalAlignment="Top"
Width="227" Height="21" Grid.ColumnSpan="2" FontSize="11" Click="btnScanFP1_Click"
Background="{x:Null}" BorderBrush="#FFFF9800" Foreground="#FFFF9800"
Style="{StaticResource Button.Hoverless}"/>
您已将该键定义为“Button.Hoverless”,它是DottedXamlName的类型。这种类型的规范用于属性和事件限定参考,也用于附加成员。所以删除。从你的关键名字。 – user1672994
此外,在windows.Resources中创建的资源是一个键控资源,因此它将自动应用。所以,当你需要这种风格时,你应该将其定义为'Style =“{StaticResource ResourceKeyName}”'。如果你想申请所有的按钮,然后删除键属性。 – user1672994
您明确地将按钮上的背景设置为'#FFFF9800',其具有[更高的优先级](https://msdn.microsoft.com/library/ms743230%28v=vs.100%29.aspx#listing )比风格触发器中的设置者要多。使用'Buttonbase'作为'TargetType'可能有点奇怪,但不应该是一个问题,因为'Button'从'ButtonBase'继承。 –