检查字符串是否包含阵列中的任何字母 - JAVA

Question

String [] V = {"a","e","i","o","u"}; 

    Scanner input = new Scanner(System.in); 
    String A; 
    System.out.println("Enter any letters"); 
    A=input.next(); 

    if(A.contains(V)) { 
     System.out.println("success"); 
    } 

底线。如果有在“V”串的字母是“A”我希望它继续以“成功”

Answer 1

尝试使用foreach循环是这样的：

 for (String string : V) { 

      if(A.contains(string)) { 
       System.out.println("success"); 
      } 
     } 

因为在方法contains(CharSequence)类型字符串不适用于参数（String []）。

Answer 2

它工作作出一些改变你的代码

String [] V = {"a","e","i","o","u"}; 
    boolean flag = false; 

    Scanner input = new Scanner(System.in); 
    String A; 
    System.out.println("Enter any letters"); 
    A=input.next(); 

    for(String temp:V) 
    { 
     if (A.contains(temp)) { 
      flag = true; 
      break; 
     } 
    } 

    if(flag) 
     System.out.println("Success"); 
    else 
     System.out.println("Not Success");