Python 2.7 Unicode字典

Question

我在想如何在Python 2.7中对字典进行编码。当我做到以下几点：

# coding=ISO-8859-1 
Programmer = {'v': ["1","2x","3","4","5"]} 
Programmer.update({'x': ["1","2x","3","4","5"]}) 
Programmer.update({'y': ["1","2x","3","4","5"]}) 
Programmer.update({'z': ["1","2x","3","4","5"]}) 
Programmer.update({'æ': ["1","2x","3","4","5"]}) 
Programmer.update({'ø': ["1","2x","3","4","5"]}) 
Programmer.update({'å': ["1","2x","3","4","5"]}) 
print Programmer 

我得到：

{'v': ['1', '2x', '3', '4', '5'], '\xe5': ['1', '2x', '3', '4', '5'], '\xf8': ['1', '2x', '3', '4', '5'], '\xe6': ['1', '2x', '3', '4', '5'], 'y': ['1', '2x', '3', '4', '5'], 'x': ['1', '2x', '3', '4', '5'], 'z': ['1', '2x', '3', '4', '5']} 

而我想要的是：

{'v': ['1', '2x', '3', '4', '5'], 'å': ['1', '2x', '3', '4', '5'], 'ø': ['1', '2x', '3', '4', '5'], 'æ': ['1', '2x', '3', '4', '5'], 'y': ['1', '2x', '3', '4', '5'], 'x': ['1', '2x', '3', '4', '5'], 'z': ['1', '2x', '3', '4', '5']} 

编辑：

这是我工作的代码：

# -*- coding: cp1252 -*- 
from PyQt4 import QtCore, QtGui 
import locale 

global Programmer 
Programmer = {u'v': ["1","2x","3","4","5"]} 
Programmer.update({u'x': ["1","2x","3","4","5"]}) 
Programmer.update({u'y': ["1","2x","3","4","5"]}) 
Programmer.update({u'z': ["1","2x","3","4","5"]}) 
Programmer.update({u'æ': ["1","2x","3","4","5"]}) 
Programmer.update({u'ø': ["1","2x","3","4","5"]}) 
Programmer.update({u'å': ["1","2x","3","4","5"]}) 

class Dialog(QtGui.QDialog): 
    NumGridRows = 3 
    NumButtons = 3 

    def __init__(self): 
     super(Dialog, self).__init__() 
     styleComboBox = QtGui.QComboBox() 
     styleComboBox.addItem("UI Item01") 
     styleLabel = QtGui.QLabel("&UI Text:") 
     styleLabel.setBuddy(styleComboBox) 
     opgaveComboBox = QtGui.QComboBox() 
     opgaveComboBox.addItem(u"v") 
     opgaveComboBox.addItem(u"x") 
     opgaveComboBox.addItem(u"å") 

     opgaveLabel = QtGui.QLabel("&Opgave:") 
     opgaveLabel.setBuddy(opgaveComboBox) 

     self.programComboBox = QtGui.QComboBox() 
     self.programComboBox.addItem("UI item02") 
     programLabel = QtGui.QLabel("&Program:") 
     programLabel.setBuddy(self.programComboBox) 


     opgaveComboBox.activated[str].connect(self.changeOpgave) 

     topLayout = QtGui.QHBoxLayout() 
     topLayout.addWidget(styleLabel) 
     topLayout.addWidget(styleComboBox) 
     #topLayout.addStretch(1) 

     topLayoutB = QtGui.QHBoxLayout() 
     topLayoutB.addWidget(opgaveLabel) 
     topLayoutB.addWidget(opgaveComboBox) 
     #topLayoutB.addStretch(1) 

     topLayoutC = QtGui.QHBoxLayout() 
     topLayoutC.addWidget(programLabel) 
     topLayoutC.addWidget(self.programComboBox) 



     mainLayout = QtGui.QGridLayout() 
     mainLayout.addLayout(topLayout, 0, 0, 1, 2) 
     mainLayout.addLayout(topLayoutB, 1, 0, 1, 2) 
     mainLayout.addLayout(topLayoutC, 2, 0, 1, 2) 
     mainLayout.setRowStretch(1, 1) 
     mainLayout.setRowStretch(2, 1) 
     mainLayout.setColumnStretch(0, 1) 
     mainLayout.setColumnStretch(1, 1) 
     self.setLayout(mainLayout) 



     self.changeStyle('Cleanlooks') 
     self.setWindowTitle("temp test") 

    def changeOpgave(self, opgaveName): 
     self.programComboBox.clear() 
     print "begin 01" 
     print Programmer[opgaveName] 

     if not opgaveName in Programmer: 
      print "begin 02" 
      self.programComboBox.addItem("Andet") 
     else: 
      print "go" 
      for item in Programmer[opgaveName]: 
       self.programComboBox.addItem(item) 

    def changeStyle(self, styleName): 
     QtGui.QApplication.setStyle(QtGui.QStyleFactory.create(styleName)) 
     self.changePalette() 

    def changePalette(self): 
     QtGui.QApplication.setPalette(QtGui.QApplication.style().standardPalette()) 

if __name__ == '__main__': 

    import sys 

    app = QtGui.QApplication(sys.argv) 
    dialog = Dialog() 
    dialog.show() 
    sys.exit(dialog.exec_()) 

我得到

KeyError: PyQt4.QtCore.QString(u'v') 
KeyError: PyQt4.QtCore.QString(u'x') 
KeyError: "PyQt4.QtCore.QString(u'\xe5') 

当试图从 “opgave” 列表

Answer 1

ComboBox回调函数是一个PyQt4.QtCore.QString()对象，而不是一个unicode字符串。另一方面，您的字典应该使用unicode()键（这是正确的做法）。

转换的QString()对象为Unicode值第一：

def changeOpgave(self, opgaveName): 
    opgaveName = unicode(opgaveName) 

这工作，因为QString()对象已持有的Unicode数据，并提供用Python的右勾拳进行这种转换，而无需重新编码数据用一个明确的编解码器。

一旦opgaveName值是一个unicode密钥，您可以使用它来与您的字典进行比较。

请注意，你可以定义词典不.update()电话：

Programmer = { 
    u'v': ["1","2x","3","4","5"], 
    u'x': ["1","2x","3","4","5"], 
    u'y': ["1","2x","3","4","5"], 
    u'z': ["1","2x","3","4","5"], 
    u'æ': ["1","2x","3","4","5"], 
    u'ø': ["1","2x","3","4","5"], 
    u'å': ["1","2x","3","4","5"], 
} 

的global关键字已经没有意义了，你正在使用它;该关键字只在函数内部有意义，在这里是多余的。

Answer 2

（误差在线路79扔）选择可能是这样的：

print "{", 
for key, value in Programmer.items(): 
    print "'%s'" % key, ':', value, ',', 
print "}" 

当你打印然后这将打印str(Programmers)但内部字典使用repr(key)和repr(value)。内容不会改变，只会以不同的方式打印。