如何在特定标签栏上打开应用程序？ iOS Objective-C

Question

我想让应用程序在第三个标签栏上打开，而不是第一个。无论我将这些应用程序放在标签栏上的顺序如何，左边的第一个总是首先打开。谁能帮忙？以下是标签条形码。

self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]]; 
// Override point for customization after application launch. 

UIViewController *viewController1 = [[FirstViewController alloc] initWithNibName:@"FirstViewController" bundle:nil]; 

UIViewController *viewController2 = [[SecondViewController alloc] initWithNibName:@"SecondViewController" bundle:nil]; 

UIViewController *viewController3 = [[ThirdViewController alloc] initWithNibName:@"ThirdViewController" bundle:nil]; 

UIViewController *viewController4 = [[FourthViewController alloc] initWithNibName:@"FourthViewController" bundle:nil]; 

UITableViewController *viewController5 = [[FifthViewController alloc] initWithNibName:@"FifthViewController" bundle:nil]; 


self.tabBarController = [[UITabBarController alloc] init]; 
self.tabBarController.viewControllers = [NSArray arrayWithObjects:viewController3, viewController4, viewController1, viewController2, nil]; 
self.window.rootViewController = self.tabBarController; 

Answer 1

你尝试

[self.tabBarController setSelectedIndex:2]; 

Answer 2

只需添加[self.tabBarController setSelectedIndex:2];

2，因为数组从0开始;