解析PHP中的JSON字符串以显示其内容

我试图使用json_decode 但我认为[]在结果的任何一端都与它有关。解析PHP中的JSON字符串以显示其内容

我需要访问此JSON的某些部分。

在PHP中我做的：

<?php 
    $arr = json_decode($json, true); 
    print $arr['ua']['rawUa']; 
?>

实际的JSON（从这里开始）为：

[ 
    { 
    "meta": { 
     "name": "ua-parser", 
     "repo": "https://github.com/tobie/ua-parser", 
     "version": "0.3.5" 
    }, 
    "ua": { 
     "rawUa": "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_11_1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/52.0.2718.0 Safari/537.36", 
     "string": { 
     "family": "Chrome", 
     "major": "52", 
     "minor": "0", 
     "patch": "2718" 
     }, 
     "family": "Chrome", 
     "major": 52, 
     "minor": 0, 
     "patch": 2718, 
     "device": { 
     "family": "Other" 
    } 
    }, 
    "os": { 
    "string": { 
     "family": "Mac OS X", 
     "major": "10", 
     "minor": "11", 
     "patch": "1", 
     "patchMinor": null 
    }, 
    "family": "Mac OS X", 
    "major": "10", 
    "minor": "11", 
    "patch": "1" 
    } 
}, 
{ 
    "meta": { 
    "name": "ua-parser-js", 
    "repo": "https://github.com/faisalman/ua-parser-js", 
    "version": "" 
    } 
}, 
{ 
    "meta": { 
    "name": "platform.js", 
    "repo": "https://github.com/bestiejs/platform.js/", 
    "version": "1.3.0" 
    }, 
    "ua": { 
     "name": "Chrome", 
     "version": "52.0.2718.0", 
     "layout": "Blink" 
    }, 
    "os": { 
     "os": { 
     "architecture": 32, 
     "family": "OS X", 
     "version": "10.11.1" 
     } 
    }, 
    "device": { 
     "product": null, 
     "manufacturer": null, 
     "description": "Chrome 52.0.2718.0 on OS X 10.11.1" 
    } 
    } 
]

来源

2016-04-28 SAFC

由于包封的'[...]'的结果是一个数组，只有1元件是它虽然。因此，要访问第一个元素，请使用'$ arr [0] ['ua'] ['key']'。使用'print_r'输出变量有助于在代码中找到错误... – giorgio

尝试使用：

print $arr[0]['ua']['rawUa'];

来源

2016-04-28 12:23:55 kadamb

您的传奇，非常感谢 – SAFC

只使用第指数0.你的数组第一个索引从0开始。

$arr = json_decode($json, true); 

echo $arr[0]['ua']['rawUa'];

来源

2016-04-28 12:25:35

试试这个，你必须从指数零获取数据，检查尝试打印阵列var_dump($arr);

$arr = json_decode($data, true); 

print $arr[0]['ua']['rawUa'];

来源

2016-04-28 12:25:47

使用foreach循环读取所有记录。

$arr = json_decode($json, true); 

foreach($arr as $row) 
{ 
    if(isset($row['ua']['rawUa']) 
    { 
     echo $row['ua']['rawUa']; 
    } 
}

对于单记录使用array index [0]

print $arr[0]['ua']['rawUa'];

来源

2016-04-28 12:25:48 RJParikh

的var_dump（$ ARR）;

结果部分：

array (size=3) 
    0 => 
    array (size=3) 
     'meta' => 
     array (size=3) 
      'name' => string 'ua-parser' (length=9) 
      'repo' => string 'https://github.com/tobie/ua-parser' (length=34) 
      'version' => string '0.3.5' (length=5) 
     'ua' => 
     array (size=7) 
      'rawUa' => string 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_11_1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/52.0.2718.0 Safari/537.36' (length=119)

来源

2016-04-28 12:28:39 Metin

解析PHP中的JSON字符串以显示其内容

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