Codeigniter，调用多个数据库的

Question

我对codeigniter很新，但处理有关多个数据库的问题。这些数据库位于同一主机上。

我已经改变了database.php中的文件，从“默认”新组预留有一个额外的组被称为“社会”

$active_group = 'default'; 
$active_group = 'social'; 
$active_record = TRUE; 

$db['default']['hostname'] = 'xxxx'; 
$db['default']['username'] = 'xxx'; 
$db['default']['password'] = 'xxxx'; 
$db['default']['database'] = 'mysql'; 
$db['default']['dbdriver'] = 'mysqli'; 
$db['default']['dbprefix'] = ''; 
$db['default']['pconnect'] = TRUE; 
$db['default']['db_debug'] = FALSE; 
$db['default']['cache_on'] = FALSE; 
$db['default']['cachedir'] = ''; 
$db['default']['char_set'] = 'utf8'; 
$db['default']['dbcollat'] = 'utf8_general_ci'; 
$db['default']['swap_pre'] = ''; 
$db['default']['autoinit'] = TRUE; 
$db['default']['stricton'] = FALSE; 

$db['social']['hostname'] = 'xxx'; 
$db['social']['username'] = 'xxx'; 
$db['social']['password'] = 'xxx'; 
$db['social']['database'] = 'social'; 
$db['social']['dbdriver'] = 'mysqli'; 
$db['social']['dbprefix'] = ''; 
$db['social']['pconnect'] = TRUE; 
$db['social']['db_debug'] = FALSE; 
$db['social']['cache_on'] = FALSE; 
$db['social']['cachedir'] = ''; 
$db['social']['char_set'] = 'utf8'; 
$db['social']['dbcollat'] = 'utf8_general_ci'; 
$db['social']['swap_pre'] = ''; 
$db['social']['autoinit'] = TRUE; 
$db['social']['stricton'] = FALSE; 

现在，在我的代码调用DBS

public function __construct() 
{ 
    $dbgroup = !file_exists(".git") ? "default" : "development"; 
    $this->_time = microtime(true); 
    $this->_db =& DB($dbgroup); 

    $dbgroup = "social"; 
    $this->_time = microtime(true); 
    $this->_dbs =& DB($dbgroup); 

我做错了什么，为什么我不能使用_dbs从第二个数据库获取数据？请记住......在这里完全编码新手！这不是我的日常工作:)

更新！ 按照stackoverflow.com/a/8269596中所述尝试调用此函数中的db，但仍然无法使其工作。

public function getUsers($userid = NULL) 
{ 
    if (empty($userid)) { 
       $rs = $this->load->database('social', TRUE); 
     ->select("id, username") 
     ->from("user") 
     ->get(); 
     $userid = $rs->result(); 
    return $userid; 
    } 
    elseif (isset($userid)) { 
       $rs = $this->load->database('social', TRUE); 
     ->select("id, username") 
     ->from("user") 
     ->where('id', $userid) 
     ->get(); 
     $userid = $rs->result(); 
    return $userid; 
    } 
} 

Answer 1

我认为这应该工作：

public function getUsers($userid = NULL) 
{ 
    $rs = $this->load->database('social', TRUE); 
    if (empty($userid)) { 
     $rs->select("id, username") 
     ->from("user") 
     ->get(); 
     $userid = $rs->result(); 
    return $userid; 
    } 
    elseif (isset($userid)) { 
     $rs->select("id, username") 
     ->from("user") 
     ->where('id', $userid) 
     ->get(); 
     $userid = $rs->result(); 
    return $userid; 
    } 
}