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下面我们可以找到我实现hashmap的代码。我不完全确定它为什么是seg。断裂。我相信这是与构造函数或析构函数有关的，但似乎无法完全确定。HashMap实现中的分段错误C++
typedef struct _node
{
char *key;
int value; /* For this, value will be of type int */
struct _node *next; /* pointer to the next node in the list */
} node;
/* HashMap class */
class HashMap
{
private:
node ** hashTable;
int numSlots;
public:
/* Initializes a hashmap given its set size */
HashMap(int size)
{
numSlots = size;
hashTable = new node*[size] ;
for (int i = 0; i < size; i++)
{
hashTable[i] = NULL;
}
}
/* Deconstructor */
~HashMap()
{
for (int i = 0; i < numSlots; i++)
{
node *temp = hashTable[i];
if (temp != NULL)
{
delete temp;
}
}
delete [] hashTable;
}
/*** Hash function. ***/
int hash(char *s)
{
int i;
int sum = 0;
for (i = 0; * (s + i) != '\0'; i++)
{
sum += *(s + i);
}
return (sum % numSlots);
}
/*
*Free all the nodes of a linked list. Helper method for *deconstructor
*/
void free_list(node *list)
{
node *temp;
char *tempKey;
int tempValue;
while (list != NULL)
{
temp = list;
tempKey = temp->key;
tempValue = temp->value;
list = list->next;
if (tempKey != NULL)
{
delete(tempKey);
}
delete(temp);
}
}
/* Create a single node. */
node *create_node(char *key, int value)
{
node *result = new node();
result->key = key;
result->value = value;
result->next = NULL;
return result;
}
/*
*Stores given key/value pair in hashmap
*returns boolean for success/failure
*/
void set (char* key, int value)
{
int keyValue = hash(key);
node *current = hashTable[keyValue];
node *original = current;
node *newNode;
if (current == NULL)
{
hashTable[keyValue] = create_node(key, value);
}
else
{
while (current != NULL)
{
current = current -> next;
}
if (current == NULL)
{
newNode = create_node(key, value);
newNode -> next = original;
hashTable[keyValue] = original;
}
}
}
/* Return a float value representing the load factor
*(item in hash map)/(size of hash map) of the data structure.
*/
float load()
{
float numUsed = 0.0;
for (int i = 0; i < numSlots; i++)
{
if (hashTable[i] != NULL)
{
numUsed++;
}
}
return (numUsed/numSlots);
}
/* Removes value corresponding to inputted key from table */
int remove (char* key)
{
int keyValue = hash(key);
node *listOfInterest = hashTable[keyValue];
if (listOfInterest == NULL)
{
return -999;
}
int toReturn = listOfInterest -> value;
delete(listOfInterest);
return toReturn;
}
/*
* Look for a key in the hash table. Return -999 if not found.
* If it is found return the associated value.
*/
int get(char *key)
{
int keyValue = hash(key);
node *listOfInterest = hashTable[keyValue];
while (listOfInterest != NULL)
{
if (listOfInterest != NULL)
{
return listOfInterest->value;
}
listOfInterest = listOfInterest -> next;
}
return -999;
}
/* Prints hash table */
void print_hash_table()
{
int i;
node *listIterator = NULL;
for (i = 0 ; i < numSlots ; i++)
{
listIterator = hashTable[i];
while (listIterator != NULL)
{
printf("%s %d\n", listIterator->key, listIterator -> value);
listIterator = listIterator -> next;
}
}
}
};
请给我们一些想法，看看错误在哪里;有太多的代码期望很多人通过它看。 –
解决这些问题的正确工具是您的调试器。在*堆栈溢出问题之前，您应该逐行执行您的代码。如需更多帮助，请阅读[如何调试小程序（由Eric Lippert撰写）]（https://ericlippert.com/2014/03/05/how-to-debug-small-programs/）。至少，您应该\编辑您的问题，以包含一个[最小，完整和可验证]（http://stackoverflow.com/help/mcve）示例，该示例再现了您的问题，以及您在调试器。 –
如何调试分段错误取决于您的平台以及某些情况下的偏好。你还没有告诉我们任何关于这件事。 –