我该如何洗牌变量列表的索引？

Question

如何降低索引列表？用此代码和变量列表

#turns string to list 
list=[] 
#gets the sentence to count and what to count and deletes punctuation 
punctuations = '''!()-[]{};:'"\,<>./?@#$%^&*_~''' 
sentence=input("Enter sentence to count: ") 
sentence=sentence.lower() 

no_punct = "" 
for char in sentence: 
    if char not in punctuations: 
     no_punct = no_punct + char 

list=no_punct.split() 

#this shows whether it is there or not 
index=[index+1 for index,list in enumerate(list)] 
print("the indices are ",index) 

Answer 1

以下代码适用于我。 random.shuffle有问题，但我在这里工作。记住它不会返回任何东西，所以你必须先使用它，然后在洗牌后打印。

import random 

#turns string to list 
list=[] 
#gets the sentence to count and what to count and deletes punctuation 
punctuations = '''!()-[]{};:'"\,<>./?@#$%^&*_~''' 
sentence=input("Enter sentence to count: ") 
sentence=sentence.lower() 

no_punct = "" 
for char in sentence: 
    if char not in punctuations: 
     no_punct = no_punct + char 

list=no_punct.split() 

#this shows whether it is there or not 
index=[index+1 for index,list in enumerate(list)] 
print("the indices are ",index) 

print(index) 
random.shuffle(index) 
print(index) 

编辑：这可能会使它成为一个重复的问题，如评论中所述。