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查看大量现有问题并未看到完全相同的场景。我正在研究Python的基础知识,并试图创建无处不在的Rock,Paper,Scissors游戏。但是,我得到的变量等于用户的猜测,我无法与代表计算机猜测的随机选择的项目进行比较。一切都评估为“你赢了!:)”,即使它不应该表明这两个变量永远不会相等。我试过没有任何运气使用str(computer_choice)。Python - 将字符串与列表中的随机项目进行比较
下面的代码的全部:
import time
import random
rps = ['Rock', 'Paper', 'Scissors']
computer_choice = random.sample(rps, 1)
print("Let's play some Rock, Paper, Scissors")
print("Hit enter when ready:")
input("")
print("Rock...")
time.sleep(1)
print("Paper...")
time.sleep(1)
print("Scissors...")
time.sleep(.75)
print("SHOOT!")
print("Which is it?")
user_choice = input(">>>")
while True:
valid_check = user_choice in rps
if valid_check == True:
break
else:
print('Bad input, try again:')
user_choice = input(">>>")
print("The computer picked: %s" % computer_choice)
if user_choice == computer_choice:
print("It's a draw!")
elif user_choice == 'Rock':
if computer_choice == 'Paper':
print("You lose :(")
else:
print("You win! :)")
elif user_choice == 'Paper':
if computer_choice == 'Scissors':
print("You lose :(")
else:
print("You win! :)")
elif user_choice == 'Scissors':
if computer_choice == 'Rock':
print("You lose :(")
else:
print("You win! :)")
完美工作,解释有意义。猜猜我是将一个列表与一个总是假的字符串进行比较。谢谢! – mannayz