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我是phonegap上的新手，我遇到一个按钮出现问题。当我在浏览器上执行时，它工作完美，并正确插入到我的数据库中，但是当我使用phonegap开发者时，它不起作用，没有任何反应......有人可以帮助我吗？Phonegap onclick不能正常工作
HTML代码：
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<meta name="format-detection" content="telephone=no" />
<meta name="msapplication-tap-highlight" content="no" />
<!-- WARNING: for iOS 7, remove the width=device-width and height=device-height attributes. See https://issues.apache.org/jira/browse/CB-4323 -->
<!--<meta name="viewport" content="user-scalable=no, initial-scale=1, maximum-scale=1, minimum-scale=1, width=device-width, height=device-height, target-densitydpi=device-dpi" />-->
<link rel="stylesheet" type="text/css" href="css/form_cadastrar.css" />
<link rel="stylesheet" href="css/jquery.mobile-1.2.1.min.css" />
<script src="js/jquery-1.8.3.min.js"></script>
<script src="js/jquery.mobile-1.2.1.min.js"></script>
<title>Cadastro</title>
</head>
<body>
<form id="formCliente" >
<div id="control">
<div class="control-group">
<div class="cad-titulo">
<span>Posso te conhecer?</span>
</div>
</div>
<div class="control-group">
<label class="control-label">
Nome
</label>
<div class="controls">
<input type="text" autofocus name="nome" id="nome" class="campos" required="required">
</div>
</div>
<div class="control-group">
<label class="control-label">
Sobrenome
</label>
<div class="controls">
<input type="text" name="sobrenome" id="sobrenome" class="campos" required="required">
</div>
</div>
<div class="control-group">
<label class="control-label">
CPF
</label>
<div class="controls">
<input type="text" placeholder="888.888.888-88" name="cpf" id="cpf" class="campos" required="required">
</div>
</div>
<div class="control-group">
<label class="control-label">
Email
</label>
<div class="controls">
<input type="email" name="email" id="email" class="campos" required="required">
</div>
</div>
<div class="control-group">
<label class="control-label">
Crie uma senha
</label>
<div class="controls">
<input type="password" name="senha" id="senha1" class="campos">
</div>
</div>
<div class="control-group">
<label class="control-label">
Repita a senha
</label>
<div class="controls">
<input type="password" name="senha2" id="senha2" class="campos">
</div>
</div>
<div class="control-group">
<input onclick="enviar()" type="button"><span>ENVIAR</span></button>
</div>
<div class="control-group">
<button onClick="history.go(-1)" type="button" class="btn btn-danger"><span>VOLTAR</span></button>
</div>
</div>
</div>
</form>
</body>
</html>
<script>
function enviar(){
var formula = $('#formCliente').serialize();
$.ajax({
type:'POST',
data: formula,
url:'http://localhost/teste/www/cadastrar.php',
success: function(data){
if(data == '' || data == 0){
alert('Occoreu um erro no Banco de Dados');
window.location = "";
}
if(data == 1){
alert('registro salvo com sucesso');
window.location.href = "login.html";
}
}
});
}
</script>
PHP代码：
<?php
$hostname = 'localhost';
$username = 'root';
$password = 'pass';
$database = 'mydb';
try {
$pdo = new PDO("mysql:host=$hostname;dbname=$database", $username,
$password, array(PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES utf8"));
//echo 'Conexao efetuada com sucesso!';
}
catch(PDOException $e)
{
echo $e->getMessage();
}
$sql = 'INSERT INTO usuario (nome, sobrenome, cpf, email, senha)' ;
$sql .= 'VALUES (:nome, :sobrenome, :cpf, :email, :senha)';
try {
$recebeConexao = $pdo->prepare($sql);
$recebeConexao->bindParam(':nome', $_POST['nome'], PDO::PARAM_STR);
$recebeConexao->bindParam(':sobrenome', $_POST['sobrenome'],
PDO::PARAM_STR);
$recebeConexao->bindParam(':cpf', $_POST['cpf'], PDO::PARAM_STR);
$recebeConexao->bindParam(':email', $_POST['email'], PDO::PARAM_STR);
$recebeConexao->bindParam(':senha', $_POST['senha'], PDO::PARAM_STR);
$recebeConexao->execute();
if($recebeConexao == true){
$cadastro = 1;
}else{
$cadastro = 0;
}
} catch (PDOException $ex) {
echo "Erro inserção";
}
echo (json_encode($cadastro));
?>
它起作用了，我不知道该如何谢谢你，自上周以来我试图解决这个问题（试用了几乎所有的东西），而且因为这个原因，我几乎在大学上失去了我的学期。非常感谢你！ –