2012-12-03 236 views
1

下面我试图用替换字符串xxx替换精确的搜索字符串。我有类似于Java日志消息的字符串原始。正如你可以看到,如果搜索字符串是“变量”,我可以用xxx成功替换它,但是当搜索字符串是“variable.method()”或“variable.method2()”时,我无法替换它。我在这里做错了什么?Scala正则表达式replaceAllIn与特殊字符完全匹配

val original = """variable+ " is in " + variable.method() + " and " + variable.method2()""" 
val replaceStr = "xxx" 
val searchStr = "variable.method()" // This can change like in the output below 
val variableExtracter = ("(?<=^|\\s|\\+)"+searchStr+"(?=\\s|$|\\+)").r 
print("Search string : " + searchStr + "\n") 
print("Original :" + original + "\n") 
val formatted = variableExtracter.replaceAllIn(original, replaceStr) 
print("Formatted :" + formatted + "\n") 

Output: 

Search string : variable //CORRECT OUTPUT 
Original :variable+ " is in " + variable.method() + " and " + variable.method2() 
Formatted :xxx+ " is in " + variable.method() + " and " + variable.method2() 
--- 
Search string : variable.method() 
Original :variable+ " is in " + variable.method() + " and " + variable.method2() 
Formatted :variable+ " is in " + variable.method() + " and " + variable.method2() 
//EXPECTED OUTPUT: variable+ " is in " + xxx + " and " + variable.method2() 
--- 
Search string : variable.method2() 
Original :variable+ " is in " + variable.method() + " and " + variable.method2() 
Formatted :variable+ " is in " + variable.method() + " and " + variable.method2() 
//EXPECTED OUTPUT:variable+ " is in " + variable.method() + " and " + xxx 
--- 
Search string : variable.method() 
Original :variable.method()+ " has " + variable + " and " + variable.method2() 
Formatted :variable.method()+ " has " + variable + " and " + variable.method2() 
//EXPECTED OUTPUT:xxx+ " has " + variable + " and " + variable.method2() 
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您期待接收“xxx.method()”还是用“xxx”完全替换“variable.method()”? – tysonjh

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我正在尝试替换EXACT MATCH搜索字符串。所以上面我试图用xxx替换完整的“variable.method()”。 – yalkris

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您需要转义searchStr中的特殊字符 – tysonjh

回答

1

编辑:

可以使用Java Pattern quote methodPattern.quote(searchStr)来包装你与\Q\E字符串。

scala> import java.util.regex.Pattern 
import java.util.regex.Pattern 

scala> val variableExtracter = ("(?<=^|\\s|\\+)"+Pattern.quote(searchStr)+"(?=\\s|$|\\+)").r 
variableExtracter: scala.util.matching.Regex = (?<=^|\s|\+)\Qvariable.method2()\E(?=\s|$|\+) 

scala> print("Search string : " + searchStr + "\n") 
Search string : variable.method2() 

scala> print("Original :" + original + "\n") 
Original :variable+ " is in " + variable.method() + " and " + variable.method2() 

scala> val formatted = variableExtracter.replaceAllIn(original, replaceStr) 
formatted: String = variable+ " is in " + variable.method() + " and " + xxx 

scala> print("Formatted :" + formatted + "\n") 
Formatted :variable+ " is in " + variable.method() + " and " + xxx 

scala> val searchStr = "variable.method()" 
searchStr: java.lang.String = variable.method() 

scala> val variableExtracter = ("(?<=^|\\s|\\+)"+Pattern.quote(searchStr)+"(?=\\s|$|\\+)").r 
variableExtracter: scala.util.matching.Regex = (?<=^|\s|\+)\Qvariable.method()\E(?=\s|$|\+) 

scala> val formatted = variableExtracter.replaceAllIn(original, replaceStr) 
formatted: String = variable+ " is in " + xxx + " and " + variable.method2() 
+0

如果搜索字符串是“变量”,那么我将在“+ xxx.method()+”和“+ xxx.method xxx.method2()'。我希望替换行能够匹配我的搜索字符串(这是一个由开始/结尾,空格或加号隔开的单词) – yalkris

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您应该使用'Pattern.quote(searchStr)'然后逃避你的字符串文字。 – tysonjh

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@yalkris我更新了答案以反映这种方法。 – tysonjh

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