需要检查两个表格之间最喜欢哪一行

Question

我是MYSQL的新手！

我需要做一个SQL查询在那里我检查有多少喜欢一个行有（之间两个表）

我发现长得很像我的另一个问题，但我不能让它返回任何东西（甚至尽管它没有产生错误

查询：

SELECT * 
    FROM likes 
INNER JOIN (SELECT likes.like_id, 
        COUNT(*) AS likes 
       FROM likes 
     INNER JOIN uploads ON likes.upload_id=uploads.upload_id 
      WHERE uploads.upload_date >= DATE_SUB(CURDATE(), INTERVAL 8 DAY) 
      GROUP BY uploads.upload_id) x ON x.like_id = likes.like_id 
    ORDER BY x.likes DESC 

链接到原来的问题： MySQL, Need to select rows that has the most frequent values in another table

帮助深表感谢

亲切的问候， 马蒂亚斯

Answer 1

既然你没有张贴你的表结构我得想..

select someid, count(*) cnt from 
(
    select * from table1 t1 join table2 t2 on t1.someid = t2.someid 
) as q0 group by someid order by cnt desc; 

它需要调整，以适应您的架构。