2015-01-02 134 views
0

我想使用存储在数据库表中的值创建一些在线测验。每个页面将显示10个问题,每个问题后面四个可能的答案......多维数组+ Foreach

What color are apples? 
red 
yellow 
blue 
pink 

我知道如何做一个简单的阵列将显示所有的问题。或者我可以显示所有的答案。但将每组答案与适当的答案组合起来会更棘手。

有人建议我使用与foreach结合的多维数组。所以我开始检查一些相关的线索,其中包括@php PDO fetchAll() - while not working, foreach works,但我完全被雪覆盖了。

这是我想出迄今...

$Questions = array('question' => $Question, 'answers' => array($Answers)); 

foreach ($Questions as $Question => $Answers) { 
    echo $Questions.'<br />'; 
} 

但它可能有更多的错误比我可以指望。这至少在正确的轨道上?

我在下面发布我的代码。

$stmt = $pdo->prepare("SELECT T.URL, TQ.URL, TQ.QID, TQ.Question, TQ.Feedback, TA.URL, TA.QID QID2, TA.Value, TA.Answer, TA.Correct 
FROM g_tests T 
LEFT JOIN g_test_questions TQ ON TQ.URL = T.URL 
LEFT JOIN g_test_answers TA ON TA.URL = T.URL 
WHERE T.URL = 'gw-intro-1' AND TQ.QID = TA.QID 
ORDER BY TA.N"); 
$stmt->execute(array(
'MyURL'=>$MyURL 
)); 

while ($row = $stmt->fetch()) { 
    $URL = $row['URL']; 
    $QID = $row['QID']; 
    $QID2 = $row['QID2']; 
    $Question = $row['Question']; 
    $Feedback = $row['Feedback']; 
    $Value = $row['Value']; 
    $Answer = $row['Answer']; 
    $Correct = $row['Correct']; 
    $Correct = str_replace('1', 'correct', $Correct); 
    $Correct = str_replace('2', 'wrong', $Correct); 

    $Questions = array('question' => $Question, 'answers' => array($Answers)); 

    foreach ($Questions as $Question => $Answers) { 
     echo $Questions.'<br />'; 
    } 
} 

我编辑这表明我修改后的代码:

$stmt = $pdo->prepare("SELECT T.Site, T.Type, T.URL, T.Section, T.URL_Foreign, T.Title, T.Subtitle, T.Parent, T.Live, TQ.URL, TQ.QID, TQ.Question, TQ.Feedback, TA.URL, TA.QID QID2, TA.Value, TA.Answer, TA.Correct 
FROM g_tests T 
LEFT JOIN g_test_questions TQ ON TQ.URL = T.URL 
LEFT JOIN g_test_answers TA ON TA.URL = T.URL 
WHERE T.URL = 'gw-intro-1' AND TQ.QID = TA.QID 
ORDER BY TA.N"); 

$stmt->execute(array('MyURL' => $MyURL)); 

$Array = $stmt->fetchAll(PDO::FETCH_ASSOC); 

foreach ($Array as $dataset){ 
foreach ($dataset as $Column => $Value){ 
    echo "The column [$Column] contains [$Value] <br> \r\n"; 
} 
} 
+0

我才发现,原来这个代码 - 回声$问题['问题']; - 在循环内插入多个回答每个问题。当在回路外回荡时,它只是回应一个问题。我还无法显示任何答案。 –

回答

1

你可以,或者,尝试$stmt->fetchAll(PDO::FETCH_ASSOC)。这直接给你一组数据集。该结构将作如下安排:

Array ("datasetNumber" => 
    Array (
     "Row1Name" => "Row1Value", 
     "Row2Name" => "Row2Value", 
     ...     
    ) 
) 

您可以通过这种阵列的循环使用

foreach ($Array as $dataset){ 
    foreach ($dataset as $Column => $Value){ 
     echo "The column [$Column] contains [$Value] \r\n"; 
    } 
} 

因此,你可以离开了

while ($row = $stmt->fetch()) { 
    $URL = $row['URL']; 
    $QID = $row['QID']; 
    $QID2 = $row['QID2']; 
    $Question = $row['Question']; 
    $Feedback = $row['Feedback']; 
    $Value = $row['Value']; 
    $Answer = $row['Answer']; 
    $Correct = $row['Correct']; 
    $Correct = str_replace('1', 'correct', $Correct); 
    $Correct = str_replace('2', 'wrong', $Correct); 

    $Questions = array('question' => $Question, 'answers' => array($Answers)); 

    foreach ($Questions as $Question => $Answers) { 
     echo $Questions.'<br />'; 
    } 
} 
+0

谢谢,但我很困惑。我应该改变我的查询 $ stmt-> fetchAll(PDO :: FETCH_ASSOC)(“SELECT或$ stmt-> fetchAll(”SELECT任何一个给我错误消息。 –

+0

执行语句后,您可能会获取它使用'$ stmt-> fetchAll(PDO :: FETCH_ASSOC)'。这应该给你一个数组与描述的结构,你可以通过给定的函数循环。 – Tacticus

+0

我看到了。我做了更改,但它仍然是没有工作,我编辑了我原来的帖子来显示我的新代码,但我意识到我做了一些非常愚蠢的事情,而不是将我的问题和答案放在单独的数据库表中,我应该把它们全部放在一张表中,亲子关系 –