如何从数据库中获取每个总数？

Question

如何编写查询以获取下面的输出？

在数据库：

表1：

id Company_accountNo 
1 123 
2 235 
3 456 

表2：

id cheque_no company_accnopky amount 
1 258  1    100 
2 963  1    200 
3 147  2    500 
4 148  3    800 
5 852  2    300 

如何获取输出这样吗？

Account_no Total_Amount No_of_Cheque 
123   300    2 
235   800    2 
456   800    1 

在此先感谢..

Answer 1

试试这个：

SELECT 
T1.Company_accountNo As Account_no, 
sum(T2.Amount) As Total_Amount, 
count(T1.Company_accountNo) AS No_of_Cheque 
FROM Table1 T1 Inner Join Table2 T2 ON T1.id = T2.company_accnopky 
Group By T1.Company_accountNo 

我认为你是缺少集团通过您正在使用什么数据库管理系统

Answer 2

SELECT a.Company_accountNo Account_no, 
    SUM(b.amount) Total_Amount, 
    COUNT(*) No_of_Cheque 
FROM table1 a 
LEFT JOIN table2 b 
ON a.id=b.company_accnopky 
GROUP BY a.Company_accountNo 

Answer 3

请尝试：

select 
    a.Company_accountNo as Account_no, 
    SUM(b.amount) as Total_Amount, 
    COUNT(*) No_of_Cheque 
from 
    tbl1 a inner join tbl2 b on a.id=b.company_accnopky 
group by a.Company_accountNo 

Answer 4

试试这个：

select t1.Company_accountNo, SUM(t2.amount) as amount, count(t2.cheque_no) as cheque_no 
from table1 t1, table2 t2 
where t1.id=t2.company_accnopky 
group by t1.Company_accountNo