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我有3个表: -Laravel访问值对象
available_offers - ID
- 最新
- 时间
- 从
- 以
- USER_ID
requested_offer - id
- user_id
- available_offersID
用户 - ID
- 姓名
- 用户名
- 密码
- 电子邮件
这里我routes_bookedController
class routes_bookedController extends Controller
{
public function create()
{
$user = available_offers::with('user')->get();
$booked = requested_routes::with('available_offers', 'user')
->where('user_id', Auth::id())
->get();
return $booked;
return view ('routes_booked.show', compact('booked'));
}
}
这里从show.blade.php结果from routes_bookedController
[
{
"id": 3,
"user_id": 4,
"available_offersID": 3,
"created_at": null,
"updated_at": null,
"available_offers": {
"id": 3,
"date": "2017-08-08",
"time": "14:11:30",
"from": "Sabah",
"to": "Sarawak",
"user_id": 2,
"isBooked": 1,
"created_at": null,
"updated_at": null
},
"user": {
"id": 4,
"name": "admin",
"username": "user1",
"email": "[email protected]",
"created_at": "2017-08-08 06:15:49",
"updated_at": "2017-08-08 06:15:49"
}
}
]
是否可以从available_offers-> user-> name中获取名称?
这是我的模型: -
requested_routes
class requested_routes extends Model { public function available_offers() { return $this->belongsTo(available_offers::class, 'available_offersID'); } public function user() { return $this->belongsTo(User::class); } }
available_offers
class available_offers extends Model { public function user() { return $this->belongsTo(User::class); } public function requested_routes() { return $this->hasMany(requested_routes::class); } }
用户
public function available_offers() { return $this->hasMany(available_offers::class); } public function requested_routes() { return $this->hasMany(requested_routes::class); }
是的,这应该工作得很好。 – Jerodev
它应该工作,因为当你dded你可以看到用户对象具有属性名称等于管理员,所以它应该输出管理员。 –