2
我用PHP和两个参数制作了一个PHP计算器 - num1
和num2
。但是当我想计算答案没有显示的数字时。
我该怎么办?PHP开关不工作
这里是我的代码:
if ($_POST) {
$first_number = $_POST['first_number'];
$second_number = $_POST['second_number'];
$cal = $_POST['cal'];
switch ('$cal') {
case "Addition":
$result = $first_number + $second_number;
break;
case "Subtraction":
$result = $first_number - $second_number;
break;
case "Multiplication":
$result = $first_number * $second_number;
break;
case "Division":
$result = $first_number/$second_number;
break;
case "Modulation":
$result = $first_number % $second_number;
break;
}
return $result;
}
echo "$cal <br /> <br /> 1st Number: $first_number <br /> 2nd Number: $second_number <br /><br />";
echo "Answer is:" . $result;
删除引号(” $ cal') - >开关($ cal) –
非常感谢................... – Karniz
如果这对你有效,那么你可以在下面标记为答案,谢谢! –