如何整合Google将API放入我们的应用程序？

Question

IAM发展，我想使用谷歌的地方之一application.In api.I写的网址，并建立类似

连接

NSURL *URL = [NSURL URLWithString:@"https://maps.googleapis.com/maps/api/place/search/json?location=-33.8670522,151.1957362&radius=500&types=food&name=harbour&sensor=true&key=AIzaSyDbiWWIOmc08YSb9DAkdyTWXh_PirVuXpM"]; 
NSURLRequest *request=[[NSURLRequest alloc]initWithURL:URL]; 
[[NSURLConnection alloc] initWithRequest:request delegate:self]; 

But in did finish loading delegate method i cant get the data.That code is here. 
- (void)connectionDidFinishLoading:(NSURLConnection *)connection 
{ 
[connection release]; 
NSString *responseString = [[NSString alloc]initWithData:responseDataencoding:NSUTF8StringEncoding]; 
    [responseData release]; 
    SBJSON *parser = [[SBJSON alloc]init]; 
    NSDictionary *data = (NSDictionary *) [parser objectWithString:responseString error:nil]; 

} 

所以，请告诉我，我做了mistake.Why IAM没有得到数据。

Answer 1

使用ASIHTTPRequest framwork所有这些问题都自动处理

所有你所要做的仅仅是创建一个URL 和分析使用JSON响应框架

http://allseeing-i.com/ASIHTTPRequest/

Answer 2

据我所知，有几个mistaks。

1. NSString *responseString = [[NSString alloc]initWithData:responseDataencoding:NSUTF8StringEncoding];

的话responseData编码是两个世界。我不知道你是否粘贴过这种东西。

1. 我希望您已使用-(void) connection:(NSURLConnection *)connection didReceiveData:(NSData *)data委托人将数据追加到responseData对象。

2. 我认为你不需要转换成NSDictionary。您可以使用以下代码。

   NSString *content = [[NSString alloc] initWithBytes:[responseDate bytes] length:[responseDate length] encoding:NSUTF8StringEncoding]; NSLog(@"Data = %@", content); NSError *error; SBJsonParser *parser = [[SBJsonParser alloc] init]; NSDictionary *jsonD = [parser objectWithString:content error:&error];