2012-06-28 72 views
0

嘿我想通过python的urllib2库发布到Facebook的分数。Facebook发布HTTP错误400:错误的请求

import urllib2,urllib 

url = "https://graph.facebook.com/USER_ID/scores" 
data = {} 
data['score']=SCORE 
data['access_token']='APP_ACCESS_TOKEN' 
data_encode = urllib.urlencode(data) 
request = urllib2.Request(url, data_encode) 
response = urllib2.urlopen(request) 
responseAsString = response.read() 

我收到此错误:如果

response = urllib2.urlopen(request) 
    File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 124, in urlopen 
    return _opener.open(url, data, timeout) 
    File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 389, in open 
    response = meth(req, response) 
    File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 502, in http_response 
    'http', request, response, code, msg, hdrs) 
    File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 427, in error 
    return self._call_chain(*args) 
    File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 361, in _call_chain 
    result = func(*args) 
    File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 510, in http_error_default 
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp) 
urllib2.HTTPError: HTTP Error 400: Bad Request 

不知道这是与Facebook的Open Graph的或不正当的urllib2 API的使用。

+2

错误的内容是什么? – Igy

+0

尽管如此,应该从Facebook的错误错误 – Igy

回答

0

我跑了你的代码,并得到了同样的错误(没有更多的错误在身体,会发表评论,但不能我猜),所以我googled“发布Facebook的得分。”

我相信您需要先授予您的应用程序权限才能首先发布分数,除非您已经这样做了。见http://developers.facebook.com/blog/post/539/

+0

是的,没有权限。谢谢 – Abhishek

0

您可能需要提供user:agent作为某些浏览器。我记得在某个网站上运行爬虫程序时发现类似的错误,因为它检测到没有浏览器正在调用它。

+3

错误对于抓取网站可能是真的 - 但FB图形API被_designed_查询服务器端脚本(等),所以用户代理发送(或者如果有的话)根本就不重要。 – CBroe