Question

给出其实我正在寻找如何选择在mysql表中的单元格值。

请帮助...

// checking the break already taken? 

    $verify = mysqli_query($conn, "SELECT COUNT(*) AS count FROM attend WHERE EmployeeNoA='$EmployeeNoA' AND SignInDate='$BreakDate' AND BreakOut_I==''"); 
    $row = mysqli_num_rows($verify); 
    echo $row; 

     // If they didn't taken the break 
     if ($row == 0) 
     { 
     echo "<script>alert ('You Have Already 1st Break Out');</script>"; 
     } 
     else 
     { 
     $SignInDate = $BreakDate; 
     $ver = "UPDATE attend SET BreakOut_I='$BreakTime' WHERE EmployeeNoA='$EmployeeNoA' AND SignInDate='$BreakDate'"; 
     if (!mysqli_query($conn, $ver)) 
     { 
     echo mysqli_error($conn); 
     } 
     else 
     { 
     echo "<script>alert ('You have 1st Break Out to GO!');</script>"; 
     } 
     } 

我需要的行数，其中的突破就相当于为null，员工没有和日标从输入值给出

请找完整的PHP编码

<?php 

$conn = mysqli_connect("localhost", "Vijay", "vijay123", "test"); 
if (mysqli_connect_errno()) 
{ 
echo "Unable to connect the Server" . mysqli_connect_error(); 
} 

if ($_SERVER["REQUEST_METHOD"] == "POST") 
{ 

$EmployeeNoA=mysqli_real_escape_string($conn, $_POST['EmployeeNoA']); 
$EmployeeNameA=mysqli_real_escape_string($conn, $_POST['EmployeeNameA']); 
$Break=mysqli_real_escape_string($conn, $_POST['Break']); 
$SignInDay=mysqli_real_escape_string($conn, $_POST['SignInDay']); 
$BreakDate=mysqli_real_escape_string($conn, $_POST['BreakDate']); 
$BreakTime=mysqli_real_escape_string($conn, $_POST['BreakTime']); 

    if ($Break != "0") 
    { 
    $ver = mysqli_query($conn, "SELECT COUNT(*) AS count FROM attend WHERE EmployeeNoA='$EmployeeNoA' && SignInDate='$BreakDate'"); 
    $row = mysqli_fetch_assoc($ver); 
    if ($row['count'] == 0) 
    { 
    echo "<script>alert ('You are not SignIn Yet! \\n Please Sign In...');</script>"; 
    } 
    else 
    { 
    $Breaks = $Break; 
     switch ($Breaks) 
     { 
     case ($Breaks == 'breakout1'): 

     // checking the break already taken? 

     $verify = mysqli_query($conn, "SELECT COUNT(*) AS count FROM attend WHERE (EmployeeNoA='$EmployeeNoA') AND (SignInDate='$BreakDate') AND (BreakOut_I=='' OR IS NULL(BreakOut_I))"); 
     $row = mysqli_num_rows($conn, $verify); 

echo "SELECT COUNT(*) AS count FROM attend WHERE (EmployeeNoA='$EmployeeNoA') AND (SignInDate='$BreakDate') AND (BreakOut_I=='' OR ISNULL(BreakOut_I))"; 


      // If they didn't taken the break 
      if ($row == '0') 
      { 
      echo "<script>alert ('You Have Already 1st Break Out');</script>"; 
      } 
      else 
      { 
      $SignInDate = $BreakDate; 
      $ver = "UPDATE attend SET BreakOut_I='$BreakTime' WHERE EmployeeNoA='$EmployeeNoA' AND SignInDate='$BreakDate'"; 
      if (!mysqli_query($conn, $ver)) 
      { 
      echo mysqli_error($conn); 
      } 
      else 
      { 
      echo "<script>alert ('You have 1st Break Out!');</script>"; 
      echo "SELECT COUNT(*) AS count FROM attend WHERE (EmployeeNoA='$EmployeeNoA') AND (SignInDate='$BreakDate') AND (BreakOut_I=='' OR IS NULL(BreakOut_I))"; 
      } 
      } 
     break; 





     case ($Breaks == 'breakin1'): 
     echo "<script>alert ('breakin1');</script>"; 
     break; 
     case ($Breaks == 'lunchout'): 
     echo "<script>alert ('lunchout1');</script>"; 
     break; 
     case ($Breaks == 'lunchin'): 
     echo "<script>alert ('lunchin1');</script>"; 
     break; 
     case ($Breaks == 'breakout2'): 
     echo "<script>alert ('breakout2');</script>"; 
     break; 
     case ($Breaks == 'breakin2'): 
     echo "<script>alert ('breakin2');</script>"; 
     break; 
     } 

    } 

    } 
    else 
    { 
    echo "<script>alert ('Please Select the Break');</script>"; 
    } 

} 
?> 

Answer 1

试试这个

$verify = mysqli_query($conn, "SELECT COUNT(*) AS count FROM 
      attend WHERE (EmployeeNoA='$EmployeeNoA' AND 
      SignInDate='$BreakDate') AND 
      (BreakOut_I='' OR ISNULL(BreakOut_I)"); 

Answer 2

试试这个：

$verify = mysqli_query($conn, "SELECT * FROM attend WHERE (EmployeeNoA='$EmployeeNoA' AND SignInDate='$BreakDate') AND (BreakOut_I='' OR ISNULL(BreakOut_I))");