主键冲突约束

string sqlInsert = "Insert into account_details(
    account_number, 
    account_type, 
    transfer_access_code, 
    account_balance, 
    customer_id) 
SELECT 
    account_number, 
    account_type, 
    transfer_access_code, 
    account_balance, 
    customer_id 
from customer_details";

这个查询只需要从客户的详细资料（表1），并插入的它在其他表2（account_details）数据主键冲突约束

当此查询时，会引发第一次工作正常

但当第二次触发时，显示错误违反PRIMARY KEY约束'PK_account_details'。无法在对象'dbo.account_details'中插入重复键。

任何想法跳过（account_details）table1的现有数据和下一行

来源

2010-10-01 C J

什么是主键？ – 2010-10-01 12:58:52

customer_details表中的customer_id和帐户详细信息表中的account_number – 2010-10-01 12:59:43

中插入新的数据使用LEFT JOIN让你排除所有已经存在于account details表中的行。此替代（甚至可能更快）是使用NOT EXISTS。

使用NOT EXISTS

INSERT INTO account_details (
    account_number 
    , account_type 
    , transfer_access_code 
    , account_balance 
    , customer_id) 
SELECT account_number 
     , account_type 
     , transfer_access_code 
     , account_balance 
     , customer_id 
FROM customer_details cd 
WHERE NOT EXISTS (
      SELECT * 
      FROM  account_details 
      WHERE account_number = cd.account_number)

来源

2010-10-01 12:58:55

用于提及NOT EXISTS的+1。一个例子也会很好。 – 2010-10-01 13:38:49

不存在添加的示例。 – 2010-10-01 14:36:11

假设ACCOUNT_NUMBER是主键使用LEFT JOIN

INSERT INTO account_details (
    account_number 
    , account_type 
    , transfer_access_code 
    , account_balance 
    , customer_id) 
SELECT account_number 
     , account_type 
     , transfer_access_code 
     , account_balance 
     , customer_id 
FROM customer_details cd 
     LEFT OUTER JOIN account_details ad ON ad.Account_number = cd.account_number 
WHERE ad.account_number IS NULL

，这应该工作

string sqlInsert = "Insert into account_details(
    account_number, 
    account_type, 
    transfer_access_code, 
    account_balance, 
    customer_id) 
SELECT 
    cd.account_number, 
    cd.account_type, 
    cd.transfer_access_code, 
    cd.account_balance, 
    cd.customer_id 
from customer_details cd 
left outer join account_details ad 
    on cd.account_number = ad.account_number 
where ad.account_number is NULL";

来源

2010-10-01 13:00:01 Sage

啊，@Lieven，你打我几秒... – Sage 2010-10-01 13:00:35

我已经在想*这是令人毛骨悚然的*） – 2010-10-01 13:02:17

+1顺便说一句（7 ...没有2 ...没有556个字符） – 2010-10-01 13:03:07

INSERT INTO account_details (ad.account_number, ad.account_type, 
    ad.transfer_access_code, ad.account_balance, ad.customer_id) 
SELECT cd.account_number, cd.account_type, 
    cd.transfer_access_code, cd.account_balance, cd.customer_id 
FROM customer_details cd 
LEFT OUTER JOIN account_details ad 
    ON cd.account_number = ad.account_number 
WHERE ad.account_number is NULL

来源

2010-10-01 13:23:22

主键冲突约束

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