如何使用javascript清空selectpicker?出于测试目的,我有两个selectpickers,html
代码:我的第二个selectpicker的空selectpicker javascript
<select id="selectzvlntype" class="selectpicker show-tick" data-size="5" data-live-search="true" data-width="100%">
<option value="0" selected disabled>Kies type zorgverlener</option>
<?php
$q = "SELECT id_zvln_type, zvln_type
FROM tbl_zvln_types
ORDER BY zvln_type ASC";
$r = mysqli_query($dbc, $q);
while($zvln_types = mysqli_fetch_assoc($r)) { ?>
<option value="<?php echo $zvln_types['id_zvln_type']; ?>"><?php echo $zvln_types['zvln_type']; ?></option>
<?php } ?>
</select>
html
代码:
<select class="selectpicker show-tick" data-size="5" data-live-search="true" data-width="100%" id="selectzkh" onchange="ga('send', 'event', 'Select Choice', 'Select ZKH Changed', this.options[this.selectedIndex].value]);">
<option value="0" selected disabled>Kies uw zorgverlener</option>
<?php
$q = "SELECT id_zvln, zvln
FROM tbl_zvln
ORDER BY zvln ASC";
$r = mysqli_query($dbc, $q);
while($zvln = mysqli_fetch_assoc($r)) { ?>
<option value="<?php echo $zvln['id_zvln']; ?>"><?php echo $zvln['zvln']; ?></option>
<?php } ?>
</select>
我javascript
代码:
$(function() {
$('#selectzvlntype').on('change', function(){
//var selected = $(this).find("option:selected").val();
//alert(selected);
$('#selectzkh').empty();
});
});
警报工作,所以$('#selectzvlntype').on('change', function()
正在工作,但.empty();
不是..
非常感谢任何帮助
非常感谢!这个窍门! – CostCare