MYSQL UNION ALL与唯一的行

Question

我有两个表如下：

Table1 

id   date   pprice 
1   22-1-2013  54.56 
2   15-2-2013  55.64 
3   25-3-2013  57.62 

和

Table2 

id   date   dprice 
1   12-1-2013  66.56 
2   17-2-2013  68.59 
3   25-3-2013  70.25 

现在，我使用下面的查询

SELECT * FROM (
(SELECT Table1.date, Table1.pprice AS P_Price, NULL AS D_Price FROM Table1) 
UNION ALL 
(SELECT Table2.date, NULL AS P_Price, Table2.dprice AS D_Price FROM Table2) 
) results 
ORDER BY date DESC 

这将导致以下输出：

date   P_Price   D_Price 
25-3-2013  NULL    70.25 
25-3-2013  57.62   NULL 
17-2-2013  NULL    68.59 
15-2-2013  55.64   NULL 
22-1-2013  54.56   NULL 
12-1-2013  NULL    66.56 

在这种情况下，显示25-3-2013的日期两次以显示一次P_Price和一次D_Price。我试图让日期行只出现一次，同时输入的价格和没有NULL像

date   P_Price   D_Price 
**25-3-2013  57.62   70.25** 
    17-2-2013  NULL    68.59 
    15-2-2013  55.64   NULL 
    22-1-2013  54.56   NULL 
    12-1-2013  NULL    66.56 

我怎么能得到这个？

Answer 1

不幸的是MySQL不支持FULL OUTER JOIN，但是你可以按照如下达到同样的效果：

select t1.date, t1.pprice AS P_Price, t2.dprice AS D_Price 
from Table1 t1 
    left join table2 t2 on t1.date = t2.date 
union 
select t2.date, t1.pprice AS P_Price, t2.dprice AS D_Price 
from Table2 t2 
    left join table1 t1 on t2.date = t1.date 

• Simplified SQL Fiddle Demo

Answer 2

使用SUM和GROUP BY：

SELECT date, SUM(P_Price) AS P_Price, SUM(D_Price) AS D_Price 
FROM (SELECT Table1.date, Table1.pprice AS P_Price, NULL AS D_Price FROM Table1 
     UNION ALL 
     SELECT Table2.date, NULL AS P_Price, Table2.dprice AS D_Price FROM Table2 
    ) results 
GROUP BY date 
ORDER BY date DESC