2010-10-01 46 views
6

选择列名我有一个查询是这样的:从最大查询

;WITH t as 
(
select 1 as RowNumber, 1 as ObjectID, 10 as [Col1], 20 as [Col2], 20 as [Col3], 20 as [Col4] UNION ALL 
select 2 as RowNumber, 2 as ObjectID, 20 as [Col1], 30 as [Col2], 40 as [Col3], 50 as [Col4] 
) 
SELECT RowNumber, ObjectID, 
     (
     SELECT MAX(Amount) 
     FROM (
       SELECT [Col1] AS Amount 
       UNION ALL 
       SELECT [Col2] 
       UNION ALL 
       SELECT [Col3] 
       UNION ALL 
       SELECT [Col4] 
       ) d 
     WHERE Amount > 0 
     ) 
FROM t 

查询工作正常,但我想知道的是马克斯(金额)的由来。 (RowNumber,ObjectId,Amount)我想要列(Col1,Col2,Col3,Col4)的名称作为字符串。

有没有办法做到这一点?

编辑 问题来自评论:如果两列有相同的最大值,它可能是一个?是的,它可以是任何一个。只要我知道它可能来自哪里,任何列名都会执行。

使用SQL Server 2008

+0

您正在使用什么RDBMS? – 2010-10-01 20:03:33

+1

如果Col1和Col2具有相同的MAX,该怎么办?它可能是一个......? – gbn 2010-10-01 20:05:40

+0

希望你不介意我刚刚编辑你的代码,使它成为一个可运行的例子,因为我从来没有见过这种方法。随意将它滚回去! – 2010-10-01 20:20:58

回答

1

一个步骤中,您可以使用UNPIVOTOUTER APPLY组合:

;WITH t as  (
select 1 as RowNumber, 1 as ObjectID, 10 as [Col1], 20 as [Col2], 
     20 as [Col3], 20 as [Col4] UNION ALL 
select 2 as RowNumber, 2 as ObjectID, 20 as [Col1], 30 as [Col2], 
     40 as [Col3], 50 as [Col4]) 
SELECT 
    RowNumber, 
    ObjectID, 
    ColName, 
    ColAmount 
FROM t 
OUTER APPLY (
    SELECT TOP 1 
    ColName, 
    ColAmount 
    FROM 
    (
     SELECT 
     Col1, 
     Col2, 
     Col3, 
     Col4 
    ) x 
    UNPIVOT (
     ColAmount FOR ColName IN (Col1, Col2, Col3, Col4) 
    ) y 
    WHERE ColAmount > 0 
    ORDER BY ColAmount DESC 
) z 

结果:

RowNumber ObjectID ColName ColAmount 
----------- ----------- --------- ----------- 
1   1   Col2  20 
2   2   Col4  50 
+0

谢谢,这原来是最好的解决方案。不知道UNPIVOT的功能,但这正是我所需要的。 – 2010-10-04 15:31:24

5

不要MAX:使用TOP避免聚合/ GROUP BY。

它还可以处理使用WITH TIES重复

我不知道,如果你遇到了什么是伪代码或者一个子查询,但这应该做你想做的

SELECT TOP 1 -- WITH TIES if needed 
    * 
FROM 
    (
    SELECT RowNumber, ObjectID, [Col1] AS Amount, 'Col1' AS ColName 
    FROM table 
    UNION ALL 
    SELECT RowNumber, ObjectID, [Col2], 'Col2' AS ColName 
    FROM table 
    UNION ALL 
    SELECT RowNumber, ObjectID, [Col3], 'Col3' AS ColName 
    FROM table 
    UNION ALL 
    SELECT RowNumber, ObjectID, [Col4], 'Col4' AS ColName 
    FROM table 
    ) foo 
WHERE Amount > 0 
ORDER BY Amount DESC 

你的主要问题是,无论你如何操作,你都必须触碰表格4次,因为子查询只返回一个值。我看不到ROW_NUMBER解决方案(但是可能有一个虽然... :-)

+0

他的查询是每行进行的。我从来不知道你能做到这一点。 – 2010-10-01 20:16:16

+0

@Martin Smith:它有效,但我不确定如何获取列名,因为它是只允许一个值的子查询。请参阅以下链接:http://sqlblogcasts.com/blogs/simons/archive/2006/05/08/Neat-trick-to-find-max-value-of-multiple-columns.aspx或http:// sqlblogcasts。 com/blogs/simons/archive/2006/05/16/Performance-of-MAX-trick.aspx – gbn 2010-10-01 20:20:03

+0

是以前从未见过的。感谢您的链接! – 2010-10-01 20:22:59

3

这是未经测试的:但是要查看您的数据正在发生什么,这可能有所帮助。不是真正的产品代码质量:

SELECT RowNumber, ObjectID, 
     (
     SELECT MAX(Amount) 
     FROM (
       SELECT str([Col1]) + ", col1, " AS Amount 
       UNION ALL 
       SELECT str([Col2]) + ", col2" 
       UNION ALL 
       SELECT str([Col3]) + ", col3" 
       UNION ALL 
       SELECT str([Col4]) + ", col4" 
       ) 
     WHERE Amount > 0 
     ) 
FROM table 

str()是DBMS的“toString()”函数。 你的SQL看起来很奇怪,你使用的是什么DBMS?

+0

你必须有金额>'0',但这是相当整洁+ 1 – gbn 2010-10-01 20:25:59

+0

这是一个聪明的方式来做到这一点。没有考虑将列名添加为像这样的字符串。谢谢 – 2010-10-01 20:34:52

2

添加到user202553's answer

;WITH t1 as(
select 1 as RowNumber, 1 as ObjectID, 10 as [Col1], 20 as [Col2], 20 as [Col3], 20 as [Col4] UNION ALL 
select 2 as RowNumber, 2 as ObjectID, 20 as [Col1], 30 as [Col2], 40 as [Col3], 50000045 as [Col4] 
), 
t2 as(
SELECT RowNumber, ObjectID, 
     (
     SELECT TOP 1 CAST(C AS BINARY(4)) + CAST(Amount as BINARY(4)) 
     FROM (
       SELECT 'Col1' AS C, [Col1] AS Amount 
       UNION ALL 
       SELECT 'Col2' AS C, [Col2] 
       UNION ALL 
       SELECT 'Col3' AS C, [Col3] 
       UNION ALL 
       SELECT 'Col4' AS C, [Col4] 
       ) d 
     WHERE Amount > 0 
     ORDER BY Amount desc 
     ) AS Top1 
FROM t1 
) 
SELECT RowNumber, 
     ObjectID, 
     CAST(Left(Top1, 4) AS CHAR(4)) AS Col, 
     CAST(SUBSTRING(Top1,5,4) AS INT) AS Amount 
FROM t2 
+0

谢谢,这也相当干净 – 2010-10-02 00:48:44

+0

甚至整洁的字符串concat:固定长度的“编码” – gbn 2010-10-03 09:21:17