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我正在尝试从Google工作表执行一个循环,从而使用a0,a1,a2等来创建循环。我能够手动设置变量,但我无法获得正确的循环。Google表格中的循环
google.load('visualization', '1', {
packages: ['gauge']
});
google.setOnLoadCallback(queryValue);
function queryValue() {
var query = new google.visualization.Query('https://spreadsheets.google.com/spreadsheet/tq?range=B22:B37&key=0AhCv9Xu_eRnSdFNhSzNQUFd3b1ZfRHgtQURINFpzeGc&gid=7');
query.send(function (response) {
if (response.isError()) {
alert('Error in query: ' + response.getMessage() + ' ' + response.getDetailedMessage());
return;
}
var data = response.getDataTable();
//date label loop
for (var i = 0; i <= 15; i++) {
document.getElementById('b' + (i + 22)).innerHTML = data.getValue(i, 0);
console.log("i =" + b22)
}
});
queryValue1()
}
function queryValue1() {
var query = new google.visualization.Query('https://spreadsheets.google.com/spreadsheet/tq?range=A22:A37&key=0AhCv9Xu_eRnSdFNhSzNQUFd3b1ZfRHgtQURINFpzeGc&gid=7');
query.send(function (response) {
if (response.isError()) {
alert('Error in query: ' + response.getMessage() + ' ' + response.getDetailedMessage());
return;
}
var data1 = response.getDataTable();
var a1 = data1.getValue(0, 0);
var a2 = data1.getValue(1, 0);
var a3 = data1.getValue(2, 0);
var a4 = data1.getValue(3, 0);
var a5 = data1.getValue(4, 0);
var a6 = data1.getValue(5, 0);
var a7 = data1.getValue(6, 0);
var a8 = data1.getValue(7, 0);
var a9 = data1.getValue(8, 0);
var a10 = data1.getValue(9, 0);
var a11 = data1.getValue(10, 0);
var a12 = data1.getValue(11, 0);
var a13 = data1.getValue(12, 0);
var a14 = data1.getValue(13, 0);
var a15 = data1.getValue(14, 0);
var a16 = data1.getValue(15, 0);
queryValue3(a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12, a13, a14, a15, a16);
});
}
function queryValue3(met1, met2, met3, met4, met5, met6, met7, met8, met9, met10, met11, met12, met13, met14, met15, met16) {
var query3 = new google.visualization.Query('https://spreadsheets.google.com/spreadsheet/tq?range=B2:B17&key=0AhCv9Xu_eRnSdFNhSzNQUFd3b1ZfRHgtQURINFpzeGc&gid=10');
query3.send(function (response) {
if (response.isError()) {
alert('Error in query3: ' + response.getMessage() + ' ' + response.getDetailedMessage());
return;
}
var data3 = response.getDataTable();
var m1 = data3.getValue(0, 0);
var m2 = data3.getValue(1, 0);
var m3 = data3.getValue(2, 0);
var m4 = data3.getValue(3, 0);
var m5 = data3.getValue(4, 0);
var m6 = data3.getValue(5, 0);
var m7 = data3.getValue(6, 0);
var m8 = data3.getValue(7, 0);
var m9 = data3.getValue(8, 0);
var m10 = data3.getValue(9, 0);
var m11 = data3.getValue(10, 0);
var m12 = data3.getValue(11, 0);
var m13 = data3.getValue(12, 0);
var m14 = data3.getValue(13, 0);
var m15 = data3.getValue(14, 0);
var m16 = data3.getValue(15, 0);
var red22 = "<span style='color:#ff0000'> ";
var yellow22 = "<span style='color:#FF9900'> ";
var green22 = "<span style='color:#009900'> ";
此代码查询谷歌的表和页面动态变化的数据被记录的每月吸引16个计并在仪表标签改变颜色相匹配,对仪表,红色,黄色或绿色的颜色。 This is the page
正如你所看到的,我有一些改进的空间。我已经设法解决所有问题,但我缩短了几个循环。
我如何将值传递到下一个函数?在queryValue行中出现意外标识符的错误。 – 2013-03-07 04:33:11
好的,让我们退后一步。你想用数据完成什么?变量A0到A15创建后会发生什么?一旦我们弄清楚了,我们可以继续研究如何做到最好。 – jmac 2013-03-07 04:52:23
我发布了更多的代码和链接到页面。这一切正常,但我缺少两个循环。我试图让他们无济于事。 – 2013-03-08 01:15:14