1
对于我的生活,我无法弄清楚为什么张贴到这个网页不工作,我一直在尝试从Stackoverflow和互联网上找到的东西。基于html表格的插入数组
第一部分适用于“id”部分,但更新功能不适用。
PHP message: PHP Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[HY093]: Invalid parameter number: mixed named and positional parameters'
updatecompany.php(21):FR \ LS :: updateCompany(阵列,NULL)
这些是从错误日志。任何帮助将深表感谢。你的问题的
if (isset($_POST["id"]) && is_numeric($_POST["id"])) {
$id = $_POST["id"];
$vid = \Fr\LS::getCompany("id", $id);
$vname = \Fr\LS::getCompany("name", $id);
$vlogo = \Fr\LS::getCompany("logo", $id);
$vinfo = \Fr\LS::getCompany("info", $id);
$vsite = \Fr\LS::getCompany("site", $id);
$vest = \Fr\LS::getCompany("est", $id);
} elseif (isset($_POST["update"])) {
\Fr\LS::updateCompany(array(
"name" => $_POST["name"],
"logo" => $_POST["logo"],
"info" => $_POST["info"],
"site" => $_POST["site"],
"est" => $_POST["est"]
),
$_POST["id"]);
echo "<center>Company updated!";
echo "<br><a href='updatecompany.php" . $_POST["id"] ."'>go back</a></center>";
} else {
die("No server with that id.");
}
public static function updateCompany($toUpdate = array(), $company = null) {
self::construct();
if(is_array($toUpdate) && !isset($toUpdate['id'])) {
if($company == null) {
echo "No company ID set!";
}
$columns = "";
foreach($toUpdate as $k => $v) {
$columns .= "`$k` = :$k, ";
}
$columns = substr($columns, 0, -2); // Remove last ","
$sql = self::$dbh->prepare("SELECT {$columns} FROM companys WHERE `id` = ? ORDER BY `id` LIMIT 1");
$sql->bindValue(":id", $company);
foreach($toUpdate as $key => $value) {
$value = htmlspecialchars($value);
$sql->bindValue(":$key", $value);
}
$sql->execute();
} else {
return false;
}
}
这是怎么回事与列定义?我还会在'substr'上使用'rtrim'。 – chris85
..而且你不会在任何地方更新!? – Jeff