Oracle如何比较行？

Question

我有那里表。

SALESMAN_REGION 
(
     SALESMAN_ID INTEGER, 
     REGION_ID  INTEGER 
); 

SALESMAN 
(
     SALESMAN_ID INTEGER, 
     SALESMAN_NAME VARCHAR2(50)  
); 

TABLE SALES 
(
     SALE_ID  INTEGER, 
     PRODUCT_ID  INTEGER, 
     SALESMAN_ID INTEGER, 
     YEAR   INTEGER, 
     Quantity  INTEGER, 
     PRICE   INTEGER 
);  

，我需要这些信息 地区托尼有超过凯文更多的销售。我写这个查询

select s.region_id,sum(s.quantity),s.salesman_id from sales s where s.salesman_id in (
select sr.salesman_id from salesman_region sr 
inner join 
salesman sm on sm.salesman_id = sr.salesman_id 
where 
sm.salesman_name = 'Tony' or sm.salesman_name = 'Kevin') group by s.region_id ,s.salesman_id order by s.region_id; 

输出是：

REGION_ID SUM(S.QUANTITY) SALESMAN_ID 
1 10   1776    10 
2 10   1603    30 
3 20   1813    10 
4 20   1479    30 
5 30   1218    10 
6 30   1516    30 

但我不知道如何将这种或另一种方式进行比较。谁能帮我？

Answer 1

我会处理这一使用条件汇总：

select s.region_id, 
     sum(case when sm.salesman_name = 'Tony' then s.quantity else 0 end) as QTony, 
     sum(case when sm.salesman_name = 'Kevin' then s.quantity else 0 end) as QKevin 
from salesman_region sr inner join 
    salesman sm 
    on sm.salesman_id = sr.salesman_id inner join 
    sales s 
    on s.sales_man_id = sm.salesman_id 
group by s.region_id 
having (sum(case when sm.salesman_name = 'Tony' then s.quantity else 0 end) > 
     sum(case when sm.salesman_name = 'Kevin' then s.quantity else 0 end) 
     ) 

注：这个工作，它假定一个推销员只在一个区域。如果不是这样，你的数据结构不能回答你的问题，因为你不知道哪个销售区域在哪个区域。