Python的转化一个维阵列成二维阵列

Question

我有一个列表
[1,2,3,4,5,6,7,8]
欲将此转换为[[1,2， 3,4] [5,6,7,8]]在蟒蛇。有人可以帮我解决这个

Answer 1

要采取输入：

def chunks(l, n): 
    return [l[i:i+n] for i in range(0, len(l), n)] 

mylist = [1,2,3,4,5,6,7,8] 
while 1: 
    try: 
     size = int(raw_input('What size? ')) # Or input() if python 3.x 
     break 
    except ValueError: 
     print "Numbers only please" 

print chunks(yourlist, size) 

打印：

[[1, 2], [3, 4], [5, 6], [7, 8]] # Assuming 2 was the input 

甚至：

>>> zip(*[iter(l)]*size) # Assuming 2 was the input 
[(1, 2), (3, 4), (5, 6), (7, 8)] 

Answer 2

您可以使用itertools.islice：

>>> from itertools import islice 
def solve(lis, n): 
    it = iter(lis) 
    return [list(islice(it,n)) for _ in xrange(len(lis)/n)] 
... 
>>> solve(range(1,9),4) 
[[1, 2, 3, 4], [5, 6, 7, 8]] 
>>> solve(range(1,9),2) 
[[1, 2], [3, 4], [5, 6], [7, 8]] 

Answer 3

还有一种numpy的方式（如果你的列表是统一的数字或字符串列表等）。

import numpy 
a = numpy.array(lst) 
nslices = 4 
a.reshape((nslices, -1))