我有一个node.js服务器使用node-mysql提取数据并将其保存到名为FRUITS的数组中。通过readStream将数组的值通过JavaScript文件发送给客户端?
我需要这个数组的(水果)的值与我发送给使用“readStream”客户端的JavaScript文件传输..
如何做到这一点任何想法?下面
nodeController.js
function sendJSfile(req, res) {
seed_id = "valid_fruits"
var mysql = require('mysql');
var end;
var connection = mysql.createConnection({
host: 'myhost',
user: 'username',
password: 'password',
database: 'databasename'
});
connection.connect()
connection.query({
sql: 'SELECT fruit_type FROM fruit_table WHERE seed_id = ? LIMIT 0, 10',
timeout: 4000,
values: [seedid]
}, function (err, result, fields) {
var FRUITS = [];
for (var i = 0; i < result.length; i++) {
var obj = result[i]
FRUITS.push(obj.fruit_type)
}
})
res.writeHead(200, { "Content-Type": "text/javascript" });
var readStream = fs.createReadStream("./fruits.js")
readStream.on('open', function() {
readStream.pipe(res);
});
readStream.on('error', function (err) {
res.end(err);
})
Client.js
// I use a post request because I need to send data to the server then receive the javascript file back via readStream
request("myserver", "post", { apples })
.done(function (res) {
})
})
function request(url, method, data) {
return $.ajax({
url: url,
method: method,
data: data
})
}
您只能将FRUITS数组作为JSON放在fruits.js文件中,您不能发送任何其他内容,只请求一个响应。 –
好吧,将FRUITS作为json放入fruits.js中的最佳方式是什么?你有任何示例代码? – PickMeUpLittle