在Ruby on Rails 3中制作通用模型时遇到的问题

Question

我试图制作一个“通用模型”，以便它可以连接到任何数据库的任何表。首先，我做了这个类，它会连接到指定（不使用模式），另一个数据库

Db的

class Db < ActiveRecord::Base 

    self.abstract_class = true 

    attr_accessor :error 

    def initialize(item = nil) 
     @error = "" 
     connect 
     super 
    end 

    def connect 
     could_connect = true 
     @error = "" 

     begin 
      ActiveRecord::Base.establish_connection(
       :adapter => "mysql2", 
       :host  => "localhost", 
       :username => "root", 
       :password => "", 
       :database => "another_database", 
       :port => 3306, 
       :encoding => "utf8" 
      ) 
     rescue ActiveRecord::ConnectionNotEstablished 
      @error = "Could not connect to database. The connection was not established" 
      could_connect = false 
     rescue Mysql2::Error 
      @error = "Could not connect to database using MySQL2" 
      could_connect = false 
     rescue => e 
      @error = "Could not connect to database. #{e.message}." 
      could_connect = false 
     end 

     return could_connect 
    end 

end 

于是，我做了这个类从数据库继承并指定表名

Gmodel

class Gmodel < Db 

    def initialize(new_table_name) 
     ActiveRecord::Base.set_table_name(new_table_name) 
     super 
    end 

end 

最后，在控制器

MainController

class MainController < ApplicationController 

    def index 
    @users = Gmodel.new("users") 
    end 

end 

但是，它gaves我这个错误：

undefined method `stringify_keys' for "users":String 

出了什么问题？有没有更好的方法来做到这一点？提前致谢！

Answer 1

为什么不简单create an ActiveRecord::Base subclass在运行时避免所有的麻烦？

t = 'some_table' 
c = Class.new(ActiveRecord::Base) { self.table_name = t } 

然后c指AR类some_table，你可以做平常的事情：

o = c.find(1) 
# 'o' is now a wrapper for the row of some_table where 'id = 1' 

cols = c.columns.map(&:name) 
# 'cols' is now an array of some_table's column names 

这是哪里的Ruby类对象了。

如果您需要连接到另一个数据库，那么你可以把establish_connection呼叫块随着self.table_name：

t = 'some_table' 
d = 'some_other_database' 
c = Class.new(ActiveRecord::Base) do 
    establish_connection(:adapter => 'mysql2', :database => d, ...) 
    self.table_name = t 
end