2010-11-22 112 views
1

我的模型如下RoR的选择标记选项

class Question < ActiveRecord::Base 
    ANSWERS= ['Option 1', 'Option 2', 'Option 3', 'Option 4'] 
end 

给出在视图<%= select(:question, :answer, Question::ANSWERS, {:include_blank => true}) %>输出

<select name="question[answer]" id="question_answer"> 
    <option value=""></option> 
    <option value="Option 1">Option 1</option> 
    <option value="Option 2">Option 2</option> 
    <option value="Option 3">Option 3</option> 
    <option value="Option 4">Option 4</option> 
</select> 

我试图<%= select(:question, :answer, Question::ANSWERS.collect {|d| [d, Question::ANSWERS.index(d)]}, {:include_blank => true}) %> 这就产生

<select name="question[answer]" id="question_answer"> 
    <option value=""></option> 
    <option value="0">Option 1</option> 
    <option value="1">Option 2</option> 
    <option value="2">Option 3</option> 
    <option value="3">Option 4</option> 
</select> 

但我需要下面的输出

<select name="question[answer]" id="question_answer"> 
    <option value=""></option> 
    <option value="1">Option 1</option> 
    <option value="2">Option 2</option> 
    <option value="3">Option 3</option> 
    <option value="4">Option 4</option> 
</select> 

回答

3

在第二个例子中,使用:

<%= select(:question, 
      :answer, 
      Question::ANSWERS.collect {|d| [d, Question::ANSWERS.index(d) + 1]}, 
      {:include_blank => true}) %> 
+0

太好了,谢谢! – 2010-11-22 13:01:16

0

可以少用修改键值对散列您的数组像这样

ANSWERS= [1=>'Option 1', 2=>'Option 2', 3=>'Option 3', 4=>'Option 4'] 

现在使用options_for_select并获得所需的输出。