只需要加入一个成员,首先上传到他的画廊图片,但由于我是symfony的新手,因此遇到很大问题。getResult返回另一个结果,而不是SQL查询Symfony2
表:
CREATE TABLE `member` (
`member_id` int(10) NOT NULL AUTO_INCREMENT,
`name` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
PRIMARY KEY (`member_id`)
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
CREATE TABLE `image` (
`image_id` int(10) NOT NULL AUTO_INCREMENT,
`member_id` int(10) NOT NULL,
`path` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
PRIMARY KEY (`image_id`),
KEY `image_member_id_idx` (`member_id`),
CONSTRAINT `image_member_id` FOREIGN KEY (`member_id`) REFERENCES `member` (`member_id`) ON DELETE CASCADE
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
操作:
$items = $this->getDoctrine()
->getManager()
->getRepository('AcmeMyBundle:Member')
->createQueryBuilder('m')
->select('m','i')
->leftJoin('Acme\MyBundle\Entity\Image', 'i', 'WITH','i.memberId = m.memberId')
->addGroupBy('m.memberId')
->setMaxResults(10)
->getQuery()
->getArrayResult();
返回2倍以上,然后在数据库中,而不是限制的记录和分组设置 当我刚打印它->getQuery->getSQL()
返回
SELECT m0_.member_id AS member_id0,
m0_.name AS name1,
i1_.image_id AS image_id2,
i1_.path AS path3,
i1_.member_id AS member_id4
FROM member m0_
LEFT JOIN image i1_
ON (i1_.member_id = m0_.member_id)
GROUP BY m0_.member_id LIMIT 10
并且此查询返回righ t直接从数据库执行它的答案。 我需要帮助哪里出错?