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我正在写一个工具,从XML文件获取GPS坐标,并将它们发送到Google Static Maps API。我正在尝试从Google获取折线。C#谷歌静态地图编码路径计算
我发现documentation现在为止,我已经写了这双值转换成编码值是折线:
private String convertDouble(Double _input)
{
String result = String.Empty;
//value * 1e5
Int32 multiplication = Convert.ToInt32(Math.Floor(_input * 1e5));
//value to binary string
String binaryString = Convert.ToString(multiplication, 2);
//binary to hex
binaryString = BinaryStringToHexString(binaryString);
//value to hex + 1
Int32 hexConvert = Convert.ToInt32(binaryString, 16) + Convert.ToInt32("01", 16);
//value to binary string
binaryString = Convert.ToString(hexConvert, 2);
//binary string zu int[] for further calculations
Int32[] bitValues = new Int32[binaryString.Length];
for (Int32 i = 0; i < bitValues.Length; i++)
{
if (binaryString[i] == '0')
{
bitValues[i] = 0;
}
else
{
bitValues[i] = 1;
}
}
//shift binary to left
Int32[] bitValues_2 = new Int32[bitValues.Length];
for (Int32 i = 0; i < bitValues.Length - 1; i++)
{
bitValues_2[i] = bitValues[i + 1];
}
bitValues_2[bitValues_2.Length - 1] = 0;
//if input value is negative invert binary
if (_input < 0)
{
for (Int32 i = 0; i < bitValues.Length; i++)
{
if (bitValues_2[i] == 0)
{
bitValues_2[i] = 1;
}
else
{
bitValues_2[i] = 0;
}
}
}
//make blocks of 5
Int32 lengthDifference = bitValues_2.Length % 5;
Int32[] bitValues_3 = new Int32[bitValues_2.Length - lengthDifference];
for (Int32 i = bitValues_2.Length - 1; i > (bitValues_2.Length - bitValues_3.Length); i--)
{
bitValues_3[i - (bitValues_2.Length - bitValues_3.Length)] = bitValues_2[i];
}
//twist blocks
Int32[] bitValues_4 = new Int32[bitValues_3.Length];
Int32 numberOfBlocks = bitValues_3.Length/5;
Int32 counter = 0;
String[] stringValues = new String[numberOfBlocks];
for (Int32 i = numberOfBlocks - 1; i >= 0; i--)
{
for (Int32 j = i * 5; j < (i * 5) + 5; j++)
{
bitValues_4[counter] = bitValues_3[j];
counter++;
}
}
counter = 0;
//write int[] into strings for final conversion
for (Int32 i = 0; i < bitValues_4.Length; i++)
{
if (i > 0 && i % 5 == 0)
{
counter++;
}
stringValues[counter] += bitValues_4[i].ToString();
}
// blocks^0x20 (32) and convert to char
Int32 value = 0;
Int32[] intValues = new Int32[stringValues.Length];
Char[] charValues = new Char[stringValues.Length];
for (Int32 i = 0; i < stringValues.Length; i++)
{
value = Convert.ToInt32(stringValues[i], 2);
if (i < stringValues.Length - 1)
{
intValues[i] = value^32;
}
else
{
intValues[i] = value;
}
intValues[i] = intValues[i] + 63;
charValues[i] = (Char)intValues[i];
result += charValues[i];
}
return result;
}
如果我使用来自documentation
值-179.4
我得到的结果
`〜伊亚@
这是好的,但如果我用我的一个值,例如:
纬度:8.7587061 LONG:48.6331662
纬度:8.8905152 LONG:48.6226701
我得到错误的值。最后的折线应该在德国南部。但通过我的计算,多段线几乎可以接近成本。也许有一个完成的类给了我编码的坐标,我还没有找到它。
是的,我有编码的折线,因为将在XML许多不同的坐标(GPS跟踪几个小时运行,并抓住每10秒的位置)。
尝试使用'decimal'而不是'double'。 – Zer0 2014-09-05 20:34:05
@ Zer0会发生什么变化? – 2014-09-05 20:53:05
@ L.B消除基2浮点问题。 – Zer0 2014-09-05 20:54:03