我试图使用PHP和MySQL来自动生成一个像这样的列表。使用从一个MySQL查询插入到另一个查询
对象#1
- 资源#3
- 资源#5
- 资源#12
受试者#2
- 资源#7
- Resourc È#4
- 资源#1
等
下面是表:
eresources
- ERID
- etitle
个科目
- SID
- stitle
subjectmap
- SID
- ERID
下面是成功给了我所有的subje代码按字母顺序CTS:
$subjectQuery = "SELECT * FROM subjects WHERE sid != 17 ORDER BY stitle ASC";
$subjectResult = $mysqli->query($subjectQuery);
while ($subjectArray = $subjectResult->fetch_assoc()) {
print "<h5 class='subcategory'>" . $subjectArray['stitle'] . "</h5>";
print "<div class='inner'>
// Need a list of resources that match each subject ID (sid) here!
</div>";
}
现在,这里是唯一成功给了我所有的电子资源具有固定主题ID代码:
$getERBySubjectQuery = " SELECT erid FROM subjectmap WHERE sid=11 ";
$getERBySubjectResult = $mysqli->query($getERBySubjectQuery);
if($getERBySubjectResult && $getERBySubjectResult->num_rows >= 1){
while($getERBySubjectArray = $getERBySubjectResult->fetch_assoc()){
$query = " SELECT * FROM eresources WHERE erid = " .$getERBySubjectArray['erid']. " ORDER BY ertitle ASC ";
$result = $mysqli->query($query);
if($result && $result->num_rows >= 1){
while($array = $result->fetch_assoc()){
print("<a href=\"" . $array['link'] . "\">" . "<h5 class='subcategory'>" . $array['ertitle'] . "<div class='accessnote'>" . $array['access'] . "</div></h5></a>");
}}}}
当然,我不倾向于复制相同节每个主题ID(sid)。我希望自动生成主题列表以及自动生成主题的资源列表。
基本上我需要从第一节喂sid到每个主题的第二节。
谢谢你们的Frits和Djangofan的回复。非常感激! –