笨语言代码路由

Question

我想语言代码段笨添加到我的URI，但我想以某种方式 - 可能与路由 - 强制浏览器停止解释一个语言代码的路径。

我还没有成功实施任何国际化图书馆在我的笨安装，我敢肯定我的问题很简单，而不库反正来解决。

我想到的方法是简单地加载相应的出现在URI的语言代码的相应的语言文件。

例如

http://example.com/about  // Default language 
http://example.com/sv/about  // Load Swedish language 

这里的控制器逻辑：

<?php 
// ** Update ** 
// The following updated code works, as long as the language code appears 
// at the end of the URI, e.g, http://example.com/about/sv 
// 
// Ideally, I would like the language code segment to always appear first. 
// 
// There is also the problem of keeping the language selected while 
// navigating around the site… 

class Pages extends CI_Controller { 
    public function view ($page = 'home') { 

     if (!file_exists('application/views/pages/'.$page.'.php')) 
      show_404(); 

     $uri = explode("/", $_SERVER['REQUEST_URI']); 
     $lang_code = end($uri); 

     $data['title'] = $lang_code; 

     switch ($lang_code) { 
      case "sv": $the_language = "swedish"; break; 
      case "no": $the_language = "norwegian"; break; 
      default: $the_language = "english"; 
     } 

     $this->lang->load('general',$the_language); 
     $this->load->view('templates/header', $data); 
     $this->load->view('pages/'.$page, $data); 
     $this->load->view('templates/footer', $data); 
    } 
} 

?> 

我要对这个错误的方式？如果是这样，为什么？请避免预先回复。

Answer 1

我将与CI路由去：

$route['([a-z]+)/([a-z]+)'] = "pages/view/$2"; 

然后，控制器会是这个样子：

<?php if (! defined('BASEPATH')) exit('No direct script access'); 

class Pages extends CI_Controller { 

function __construct() { 
    parent::__construct(); 
    $this->language = $this->uri->segment(1); 
} 

function view($page = 'home') 
{ 
    /* other stuff */ 
    $this->lang->load('general',$this->language); 
    $this->load->view('templates/header', $data); 
    $this->load->view('pages/'.$page, $data); 
    $this->load->view('templates/footer', $data); 
} 

}