2016-08-03 131 views
1

截图:显示属性

enter image description here

选择项目从上面的ListView显示了它们在下面的数据网格特性。

XAML:

<Window x:Class="EmployeeSystem.Run_with_XML" 
     xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" 
     xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" 
     xmlns:d="http://schemas.microsoft.com/expression/blend/2008" 
     xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" 
     xmlns:local="clr-namespace:EmployeeSystem" 
     mc:Ignorable="d" 
     Title="Run with XML" Height="398.299" Width="305.91" WindowStartupLocation="CenterScreen" ResizeMode="NoResize"> 
    <Grid Height="325" VerticalAlignment="Top"> 
     <StackPanel> 
      <ListView Height="100" DisplayMemberPath="Name" ItemsSource="{Binding employees}" SelectedItem="{Binding SelectedEmployee}"/> 
      <DataGrid Height="100" ItemsSource="{Binding EmployeesView}"/> 
     </StackPanel> 

     <Button x:Name="button" Content="Create New" Height="24" Margin="112,0,111,-30" VerticalAlignment="Bottom"/> 
    </Grid> 
</Window> 

VeiwModel:

class ViewModel 
{ 
    private Employee selectedEmployee; 
    public ICollectionView EmployeesView { get; set; } 

    EmployeeManagerXML emx = new EmployeeManagerXML(); 

    public ViewModel() 
    { 
     EmployeesView = new ListCollectionView(emx.getEmployeesList()) //this is an ObservableCollection 
     { 
      Filter = obj => 
      { 
       var Employee = (Employee)obj; 

       return SelectedEmployee != null && Employee.Name == SelectedEmployee.Name; 
      } 
     }; 
    } 

    public Employee SelectedEmployee 
    { 
     get { return selectedEmployee; } 
     set 
     { 
      if (selectedEmployee != value) 
      { 
       selectedEmployee = value; 
       EmployeesView.Refresh(); 
      } 
     } 
    } 
} 

我一直拼命,现在实现这个几天...我搜索谷歌几个小时......想尽一切在stackoverflow上的相关页面...这篇文章是我最后的希望...有人请告诉我哪里出错了。我已经知道这是一个重复.. This情景是完全一样的,我做了一切完全一样的答案说...仍然是我的工作。

+0

在输出窗口中是否有任何绑定错误? – Pravin

+0

在输出窗口中没有错误 –

+0

您的ListView的ItemSource绑定到“employees”属性,您的ViewModel中的属性在哪里? – Pravin

回答

1

你应该impliment INotifyPropertyChanged接口,以反映视图

例如下面的变化,

public class ViewModel: INotifyPropertyChanged 
{ 
    public event PropertyChangedEventHandler PropertyChanged; 

    public void NotifyPropertyChanged([CallerMemberName] string propertyName = "") 
    { 
     PropertyChanged?.Invoke(this, new PropertyChangedEventArgs(propertyName)); 
    } 

    EmployeeManagerXML emx = new EmployeeManagerXML(); 

    public ViewModel() 
    { 

    } 
    private Void RefreshEmployeeList() 
    { 
     EmployeesView = new ListCollectionView(emx.getEmployeesList()) //this is an ObservableCollection 
    { 
     Filter = obj => 
     { 
      var Employee = (Employee)obj; 

      return SelectedEmployee != null && Employee.Name == SelectedEmployee.Name; 
     } 
    }; 
    } 
    private Employee selectedEmployee; 
    private ICollectionView _EmployeesView; 
    public ICollectionView EmployeesView 
    { 
     get { return _EmployeesView; } 
     set 
     { 
      _EmployeesView = value; 
      NotifyPropertyChanged(); 
     } 
    } 
    public Employee SelectedEmployee 
    { 
    get { return selectedEmployee; } 
    set 
    { 
     if (selectedEmployee != value) 
     { 
      selectedEmployee = value;     
      NotifyPropertyChanged(); 
      RefreshEmployeeList(); 
     } 
    } 
} 

MSDN

INotifyPropertyChanged接口用于通知客户,通常是结合客户,财产价值已经改变。

+0

但是,这不是什么的ObservableCollection <>是... '[SerializableAttribute] 公共类的ObservableCollection :收集,INotifyCollectionChanged, \t INotifyPropertyChanged' –

+0

您可以在'ICollectionView'的位置使用'ObservableCollection'检查[this](https://msdn.microsoft.com/en-us/library/ms668604(v = vs.110).aspx) –