如何使用C＃.net中的LINQ分组XML数据？

Question

我想读取一个xml文件使用C＃.net和LINQ的帮助，我想根据INSTANCE和CINSTANCE值在xml中分组节点。我怎样才能做到这一点？ 这是我的源模式：

<XYZ> 
    <TYPE>A</TYPE> 
    <INSTANCE>1357599</INSTANCE> 
    <CHILD>DESCRIPTION</CHILD> 
    <CINSTANCE>PQR</CINSTANCE> 
    <CPOS>0000</CPOS> 
    </XYZ> 

    <XYZ> 
    <TYPE>GP</TYPE> 
    <INSTANCE>1472422</INSTANCE> 
    <CHILD>A</CHILD> 
    <CINSTANCE>1357599</CINSTANCE> 
    <CPOS>0010</CPOS> 
    </XYZ> 

    <XYZ> 
    <TYPE>GP</TYPE> 
    <INSTANCE>1472427</INSTANCE> 
    <CHILD>A</CHILD> 
    <CINSTANCE>1357599</CINSTANCE> 
    <CPOS>0010</CPOS> 
    </XYZ> 

    <XYZ> 
    <TYPE>A</TYPE> 
    <INSTANCE>1357600</INSTANCE> 
    <CHILD>DESCRIPTION</CHILD> 
    <CINSTANCE>PQR</CINSTANCE> 
    <CPOS>0000</CPOS> 
    </XYZ> 

    <XYZ> 
    <TYPE>GP</TYPE> 
    <INSTANCE>1472425</INSTANCE> 
    <CHILD>A</CHILD> 
    <CINSTANCE>1357600</CINSTANCE> 
    <CPOS>0010</CPOS> 
    </XYZ> 

    <XYZ> 
    <TYPE>GP</TYPE> 
    <INSTANCE>1472426</INSTANCE> 
    <CHILD>A</CHILD> 
    <CINSTANCE>1357600</CINSTANCE> 
    <CPOS>0010</CPOS> 
    </XYZ> 

这应该是我的输出：

<Group> 
    <XYZ> 
<TYPE>A</TYPE> 
<INSTANCE>1357599</INSTANCE> 
<CHILD>DESCRIPTION</CHILD> 
<CINSTANCE>PQR</CINSTANCE> 
<CPOS>0000</CPOS> 
</XYZ> 

    <XYZ> 
<TYPE>GP</TYPE> 
<INSTANCE>1472422</INSTANCE> 
<CHILD>A</CHILD> 
<CINSTANCE>1357599</CINSTANCE> 
<CPOS>0010</CPOS> 
</XYZ> 

    <XYZ> 
<TYPE>GP</TYPE> 
<INSTANCE>1472427</INSTANCE> 
<CHILD>A</CHILD> 
<CINSTANCE>1357599</CINSTANCE> 
<CPOS>0010</CPOS> 
</XYZ> 
    </Group>  

    <Group> 
    <XYZ> 
<TYPE>A</TYPE> 
<INSTANCE>1357600</INSTANCE> 
<CHILD>DESCRIPTION</CHILD> 
<CINSTANCE>PQR</CINSTANCE> 
<CPOS>0000</CPOS> 
</XYZ> 

    <XYZ> 
<TYPE>GP</TYPE> 
<INSTANCE>1472425</INSTANCE> 
<CHILD>A</CHILD> 
<CINSTANCE>1357600</CINSTANCE> 
<CPOS>0010</CPOS> 
</XYZ> 

    <XYZ> 
<TYPE>GP</TYPE> 
<INSTANCE>1472426</INSTANCE> 
<CHILD>A</CHILD> 
<CINSTANCE>1357600</CINSTANCE> 
<CPOS>0010</CPOS> 
</XYZ> 
    </Group> 

我需要组XYZ节点基于INSTANCE==CINSTANCE ..是有反正写一个逻辑呢？

Answer 1

您可能正在寻找类似于下面的代码的东西，但是您的格式需要稍作更改，它需要Xml中的有效父元素。

static void Main(string[] args) 
    { 
     string xml = @"<ELEMENTS><XYZ>  <TYPE>A</TYPE>  <INSTANCE>1357599</INSTANCE>  <CHILD>DESCRIPTION</CHILD>  <CINSTANCE>PQR</CINSTANCE>  <CPOS>0000</CPOS>  </XYZ>  <XYZ>  <TYPE>GP</TYPE>  <INSTANCE>1472422</INSTANCE>  <CHILD>A</CHILD>  <CINSTANCE>1357599</CINSTANCE>  <CPOS>0010</CPOS>  </XYZ>  <XYZ>  <TYPE>GP</TYPE>  <INSTANCE>1472427</INSTANCE>  <CHILD>A</CHILD>  <CINSTANCE>1357599</CINSTANCE>  <CPOS>0010</CPOS>  </XYZ>  <XYZ>  <TYPE>A</TYPE>  <INSTANCE>1357600</INSTANCE>  <CHILD>DESCRIPTION</CHILD>  <CINSTANCE>PQR</CINSTANCE>  <CPOS>0000</CPOS>  </XYZ>  <XYZ>  <TYPE>GP</TYPE>  <INSTANCE>1472425</INSTANCE>  <CHILD>A</CHILD>  <CINSTANCE>1357600</CINSTANCE>  <CPOS>0010</CPOS>  </XYZ>  <XYZ>  <TYPE>GP</TYPE>  <INSTANCE>1472426</INSTANCE>  <CHILD>A</CHILD>  <CINSTANCE>1357600</CINSTANCE>  <CPOS>0010</CPOS>  </XYZ></ELEMENTS>"; 
     Console.WriteLine(GetGroups(xml).ToString()); 
    } 

    private static XDocument GetGroups(string xml) 
    { 
     XDocument xyzElementsDocument = XDocument.Parse(xml); 

     var results = from xyzElement1 in xyzElementsDocument.Descendants("XYZ") 
         join xyzElement2 in xyzElementsDocument.Descendants("XYZ") 
         on (string)xyzElement1.Element("INSTANCE") equals (string)xyzElement2.Element("CINSTANCE") into joinedElements 
         from joinedElement in joinedElements.DefaultIfEmpty() 
         group xyzElement1 by joinedElement != null into groupedElements 
         select new { HasCInstance = groupedElements.Key, Elements = groupedElements.Distinct() }; 

     XDocument groupDocument = new XDocument(); 
     groupDocument.Add(new XElement("GROUPS")); 
     foreach (var result in results) 
     { 
      XElement groupElement = new XElement("GROUP"); 
      groupElement.Add(result.Elements); 
      groupDocument.Root.Add(groupElement); 
     } 

     return groupDocument; 
    }